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Displaying an image by reading the file and parsing byte code?
Posted on 2006-07-23
Hi, the way I wrote the question probably is a dead give away that I dont know what I'm talking about!
Background: security on the webserver is set up so that images in a particular folder cannot be browsed and displayed in a webbrowser unless they have a username and password on the folder, and this is the way it needs to stay.
What I need to do is this: display the image file by some other means. The webserver has access to the file by name. I believe you can read the image file and display it somehow. Can someone please help me with the code for this?
Thanks heaps,
Heather.
Background: security on the webserver is set up so that images in a particular folder cannot be browsed and displayed in a webbrowser unless they have a username and password on the folder, and this is the way it needs to stay.
What I need to do is this: display the image file by some other means. The webserver has access to the file by name. I believe you can read the image file and display it somehow. Can someone please help me with the code for this?
Thanks heaps,
Heather.
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You can find out the exact path of the server to the folder, I'll call it $path.
Then create a file such as images.php, then when you want say image.jpg, call images.php?img=image.jpg.
SOURCE OF images.php:
<?php
$img = $_GET['img'];
$path = "\path to images folder leaving in trailing slash\";
$instr = fopen($path.$img,"rb");
$bytes = fread($instr,filesize($pat
header("Content-type: image/jpeg");
echo $bytes;
?>
Hope this helps :)
Gileze33.
Then create a file such as images.php, then when you want say image.jpg, call images.php?img=image.jpg.
SOURCE OF images.php:
<?php
$img = $_GET['img'];
$path = "\path to images folder leaving in trailing slash\";
$instr = fopen($path.$img,"rb");
$bytes = fread($instr,filesize($pat
header("Content-type: image/jpeg");
echo $bytes;
?>
Hope this helps :)
Gileze33.
Thanks heaps gileze.
One thing I didn't mention is that I am displaying the image amongst lots of other text, so I don't think the headers line will work for me.
I've tried just printing out the bytes without that, however, and it wont work. Can you please help?
Thanks again.
One thing I didn't mention is that I am displaying the image amongst lots of other text, so I don't think the headers line will work for me.
I've tried just printing out the bytes without that, however, and it wont work. Can you please help?
Thanks again.
Yes thats understandable.
You need to treat the images.php file as though it were an image - so simply use the HTML <img> tag to load in the image to a separate HTML page.
E.g.
<html>
<body>
Hi. Below is an image!
<br>
<img src="images.php?img=whatev
</body>
</html>
Sorry about the cheesy example :)
Gileze33.
You need to treat the images.php file as though it were an image - so simply use the HTML <img> tag to load in the image to a separate HTML page.
E.g.
<html>
<body>
Hi. Below is an image!
<br>
<img src="images.php?img=whatev
</body>
</html>
Sorry about the cheesy example :)
Gileze33.
Ok.
Make images.php with the source at the top, replacing the absolute path with one to your images folder.
Next, create file.html, with the source I put above (making sure that you change the source for the image to be one that actually exists).
Hope this helps :)
Gileze33.
Make images.php with the source at the top, replacing the absolute path with one to your images folder.
Next, create file.html, with the source I put above (making sure that you change the source for the image to be one that actually exists).
Hope this helps :)
Gileze33.
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