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Regular expression

Posted on 2006-07-23
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Last Modified: 2010-04-17
How do I do a regular exp which will  contain:

hello in either lower or uppercase
or byebye in either lower or uppercase

both can have any prefix or suffix
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Question by:noam_dz
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InteractiveMind earned 100 total points
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Like this?

([hH][eE][lL][lL][oO])|([bB][yY][eE][bB][yY][eE])
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by:InteractiveMind
ID: 17163094
What language are you using however?

Because you could simplify that down to:

(hello)|(byebye)

And specify case insensitivty to the regex compiler.
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by:InteractiveMind
ID: 17163105
Hmm.. Unless you mean that the entire string must be in either lower case or upper case, rather than potentially a mix of both?

In which case, you could do this:

(hello)|(HELLO)|(byebye)|(BYEBYE)
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by:rockiroads
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ID: 17163285
something I picked up in perl earlier

(h|H)|(e|E)|(l|L)|(l|L)|(o|O)


http://www.experts-exchange.com/Programming/Programming_Languages/Perl/Q_21921631.html


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by:owenli27
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ID: 17165221
In Java:
Pattern ptrnForm = Pattern.compile("([.\\s]*?hello[.\\s]*?)|([.\\s]*?byebye[.\\s]*?)", Pattern.CASE_INSENSITIVE);

In Perl:
if( $str =~ /(hello)|(byebye)/i )
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by:Anandhi K
Anandhi K earned 100 total points
ID: 17165816
Regex.IsMatch(Value,"(/.*?[hello|byebye]?/.*/i)", RegexOptions.IgnoreCase);


In regular expressions, a period can stand for any character. Using a period in a pattern is a way of requiring that "something" occurs here, without having to decide what. (because both can have any prefix or suffix)

the asterisk ("*") is any number of

question-mark ("?") means occurs exactly once

Advanced -- i - Case-insensitive match


Can avoid /i in case of using RegexOptions.IgnoreCase.
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by:ozo
ozo earned 100 total points
ID: 17165851
You don't need the () in
if( $str =~ /hello|byebye/i )
unless you also want to capture the match, which you can do with
if( $str =~ /(hello|byebye)/i )
But note that these would also match $str = "phellodendron"



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