Solved

PHP - sending a variable with image button

Posted on 2006-07-23
5
192 Views
Last Modified: 2010-04-17
I have a button but I want to use it to send a variable to the same page if it is pressed

<a  href="#"
onmouseover="document.sub_but1.src='buttons/reset_cream_over.gif'"
onmouseout="document.sub_but1.src='buttons/reset_cream_up.gif'"><img  src="buttons/reset_cream_up.gif"
alt="Move your mouse over me" name="sub_but1" width="82" height="32" border="0" align="absmiddle" id="sub_but1" /></a>

at the top I want to do something like

if (isset($_POST['reset']) {

//do something here

}


any ideas?

0
Comment
Question by:roscoeh23
  • 2
5 Comments
 
LVL 25

Accepted Solution

by:
InteractiveMind earned 250 total points
ID: 17163635
If you wish to submit data to the same page (or any other for that matter), then I believe you need to use a submit button, rather than an anchor.


<?php

   if ( isset( $_POST['reset'] ) )
   {
      // do something
   } else
   {
      <form action="#" type="POST">
         // create some input fields here...
         
         <input type="submit">
      </form>
   }

?>


Does that help?
0
 
LVL 25

Expert Comment

by:InteractiveMind
ID: 17163640
To make that an Image submit button, see here:

http://www.codetoad.com/html/buttons/image_submit_button.asp?x=75&y=19
0
 

Assisted Solution

by:mario_ccs
mario_ccs earned 250 total points
ID: 17215830
Change the <a  href="#"

to

<a  href="your_page.php?variable=value"

then

if (isset($_GET['variable']) {

//do something here

}
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