Determine if the second character in a string is a number

I am using VB6 and I need a way to determine if the second character in a string is a variable.  I found the following code:

result = (isnumber(Value(Left(myString, 2))))

There were no functions listed with this code so I thought it was using functions build into VB6, but it must not be the case because it does not work.

Does anyone know an easy way to determine if the second character in a string is a number?
LVL 5
bpl5000Asked:
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Patrick MatthewsConnect With a Mentor Commented:
Hi bpl5000,

If IsNumeric(Mid(myString, 2, 1)) Then
    'action for is a numeral
Else
    'action for not a numeral
End If

Regards,

Patrick
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bpl5000Author Commented:
Thanks Patrick!  This works great, but I thought Left would be the way to go.  Looks like I'm wrong (again... D'oh!).  I guess if I say "If IsNumeric(Left(myString, 2)) Then"... this is looking at the first 2 characters instead of only the second character?
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bpl5000Author Commented:
No need to answer that question my last question... I tried:

MsgBox Left(myString, 2)

and now I see it does give you the first two digits.
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