troubleshooting Question

preg_replace - replace text contains "$0.32" and "dollar 0" is interpreted as the matching text!

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rivusglobalFlag for Canada asked on
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Considering the following example, how can I get preg_replace to ignore the function of the replacement parameter that is introduced by the replacement text?

$text = "This item costs $0.99";
$html = "<b>%COST%</b>";

$html = preg_replace( "%COST%", $text, $html );

---------- the above produces the string below:

$html = "<b>This item costs %COST%.99</b>";

---------- but i want the previous code to produce this:

$html = "<b>This item costs $0.99</b>";

How can I do this?
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