troubleshooting Question

% character in sprintf

Avatar of tr5
tr5 asked on
2 Comments1 Solution602 ViewsLast Modified:
This is crazy, but I can't get a % character to appear in a sprintf() statement.
What is wrong with this:
$str = sprintf("Percentage: %0.2f%", 53.0);
echo "str = $str<br>";
prints only "str = "
The % after the 0.2f causes the problem. I tried escaping it but it doesn't work. In c you can use a % in a printf. What's the deal here?

Join our community to see this answer!
Unlock 1 Answer and 2 Comments.
Start Free Trial
Learn from the best

Network and collaborate with thousands of CTOs, CISOs, and IT Pros rooting for you and your success.

Andrew Hancock - VMware vExpert
See if this solution works for you by signing up for a 7 day free trial.
Unlock 1 Answer and 2 Comments.
Try for 7 days

”The time we save is the biggest benefit of E-E to our team. What could take multiple guys 2 hours or more each to find is accessed in around 15 minutes on Experts Exchange.

-Mike Kapnisakis, Warner Bros