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tr5
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% character in sprintf

Hi
This is crazy, but I can't get a % character to appear in a sprintf() statement.
What is wrong with this:
$str = sprintf("Percentage: %0.2f%", 53.0);
echo "str = $str<br>";
prints only "str = "
The % after the 0.2f causes the problem. I tried escaping it but it doesn't work. In c you can use a % in a printf. What's the deal here?

Thanks
tr5
PHP

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Last Comment
callrs

8/22/2022 - Mon
ASKER CERTIFIED SOLUTION
callrs

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callrs

e.g.
$str = sprintf("Percentage: %0.2f%%", 53.0);
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