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blnukem

asked on

Number Format

Hi All

I need some help with this, I have a variable value of 0.06 and would like to change it to 6 here is what I have.

CODE:

$Number = 0.06;
$Number = sprintf("%0.2f", $Number);
print $Number;


Result Now: 0.06
Wanted Result: 6


ASKER CERTIFIED SOLUTION
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ozo
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jhurst

what's wrong with $number=int($number *100);
or even
$number*=100;
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ASKER

Thanks ozo

$Number = 0.06;
$Number = sprintf("%.0f",$Number*100);
print $Number;

Works Great!