Solved

C++ ifstream error

Posted on 2006-10-20
4
974 Views
Last Modified: 2008-02-01
Heres my code:

using namespace std;                  // Global using directive
#include <iostream>                        // Header file for cout and endl
#include <iomanip>                        // Header file for I/O manipulators

int main()                                    // Start of main() function
{
string source;                              // variable for the input file
int numChar;                              // variable for number of characters

cout << "Enter the name of the source program file now: ";            //Prompt user
cin >> source;
cout << endl << endl;

//-------------------INPUT---------------------

ifstream inputfile (source);


//----------------------------------------------

return 0;                                    // Signal successful program execution

}  // End of main()








Heres my errors:

"Program06.cpp", line 28: Error: The type "std::ifstream " is incomplete.
"Program06.cpp", line 28: Error: The type "std::ifstream " is incomplete.
2 Error(s) detected.



Can anyone tell me how to fix this error

0
Comment
Question by:xneo27
[X]
Welcome to Experts Exchange

Add your voice to the tech community where 5M+ people just like you are talking about what matters.

  • Help others & share knowledge
  • Earn cash & points
  • Learn & ask questions
  • 2
4 Comments
 
LVL 22

Accepted Solution

by:
cookre earned 500 total points
ID: 17775441
#include <fstream>
0
 

Expert Comment

by:alex_kurumpelil
ID: 17775908
Was able to compile with VC++ 6.0

#include <iostream>                    // Header file for cout and endl
#include <iomanip>                    // Header file for I/O manipulators
#include <fstream>

using namespace std;               // Global using directive

int main()                              // Start of main() function
{
char szsource[256] = {0};              // variable for the input file
int numChar;                         // variable for number of characters

cout << "Enter the name of the source program file now: ";          //Prompt user
cin >> szsource;
cout << endl << endl;

string source = szsource;
//-------------------INPUT---------------------

ifstream  inputfile;
inputfile.open(source.c_str());


//----------------------------------------------

return 0;                              // Signal successful program execution

}  // End of main()
0
 

Author Comment

by:xneo27
ID: 17777135
Thanks cookre, guess it just slipped my mind or I was in too big of a hurry.
0
 
LVL 22

Expert Comment

by:cookre
ID: 17777893
That happens to all of us.  
After 36 years programming, I still do it.
But as you gain experience, you immediately recognize the causes of more and more errors.
0

Featured Post

What does it mean to be "Always On"?

Is your cloud always on? With an Always On cloud you won't have to worry about downtime for maintenance or software application code updates, ensuring that your bottom line isn't affected.

Question has a verified solution.

If you are experiencing a similar issue, please ask a related question

Whether you've completed a degree in computer sciences or you're a self-taught programmer, writing your first lines of code in the real world is always a challenge. Here are some of the most common pitfalls for new programmers.
This article will inform Clients about common and important expectations from the freelancers (Experts) who are looking at your Gig.
In this fourth video of the Xpdf series, we discuss and demonstrate the PDFinfo utility, which retrieves the contents of a PDF's Info Dictionary, as well as some other information, including the page count. We show how to isolate the page count in a…
With the power of JIRA, there's an unlimited number of ways you can customize it, use it and benefit from it. With that in mind, there's bound to be things that I wasn't able to cover in this course. With this summary we'll look at some places to go…

632 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question