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Gridview HyperLinkField

strickdd
strickdd asked
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Last Modified: 2012-08-13
I have a URL I'm saving to a DB and want to display as a clickable link on a Gridview. I want the text of the link to be "View Form" and the URL to be the value pulled back from the DB. Anyone know how to do this? Here is what I got, but is not working:

<asp:HyperLinkField DataNavigateUrlFields="FormURL" DataNavigateUrlFormatString="http://{0}"
                            HeaderText="Form URL" SortExpression="FormURL" Target="_blank" DataTextField="FormURL" />
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Commented:
<asp:Hyperlink runat="server" Text='View Form' NavigateUrl='<%#"http://" & Server.UrlEncode(Container.DataItem("fieldname"))%>' ID="Hyperlink1" Target="_new" Enabled=True/>

Author

Commented:
That doesn't work in the gridview. It says:

Error      1      System.Web.UI.WebControls.DataControlFieldCollection must have items of type 'System.Web.UI.WebControls.DataControlField'. 'asp:Hyperlink' is of type 'System.Web.UI.WebControls.HyperLink'.      C:\Inetpub\wwwroot\ScienceFair\Admin\SpecialConditions.aspx      19      
Commented:
are you putting them under template column??

here is an example..

http://www.eggheadcafe.com/community/aspnet/6/10004766/passing-parameters-from-g.aspx

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Author

Commented:
That's closer to what I need. However, in the DB i'm storing something like:

FormURL = "www.somewhere.com/page.pdf"

I need this value from the DB to be the location of the link that says "View".
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