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Gridview HyperLinkField

I have a URL I'm saving to a DB and want to display as a clickable link on a Gridview. I want the text of the link to be "View Form" and the URL to be the value pulled back from the DB. Anyone know how to do this? Here is what I got, but is not working:

<asp:HyperLinkField DataNavigateUrlFields="FormURL" DataNavigateUrlFormatString="http://{0}"
                            HeaderText="Form URL" SortExpression="FormURL" Target="_blank" DataTextField="FormURL" />
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strickdd
Asked:
strickdd
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1 Solution
 
Pra4444Commented:
<asp:Hyperlink runat="server" Text='View Form' NavigateUrl='<%#"http://" & Server.UrlEncode(Container.DataItem("fieldname"))%>' ID="Hyperlink1" Target="_new" Enabled=True/>
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strickddAuthor Commented:
That doesn't work in the gridview. It says:

Error      1      System.Web.UI.WebControls.DataControlFieldCollection must have items of type 'System.Web.UI.WebControls.DataControlField'. 'asp:Hyperlink' is of type 'System.Web.UI.WebControls.HyperLink'.      C:\Inetpub\wwwroot\ScienceFair\Admin\SpecialConditions.aspx      19      
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Pra4444Commented:
are you putting them under template column??

here is an example..

http://www.eggheadcafe.com/community/aspnet/6/10004766/passing-parameters-from-g.aspx
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strickddAuthor Commented:
That's closer to what I need. However, in the DB i'm storing something like:

FormURL = "www.somewhere.com/page.pdf"

I need this value from the DB to be the location of the link that says "View".
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