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Unable to intialize Logger

Posted on 2006-10-27
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Last Modified: 2010-05-18
Hi Experts,

I have one application in which I am trying to facilitate it thru logger..
but now application has started throwing runtime excpetion...

--------------------------------------------------------------------------
type Exception report

message

description The server encountered an internal error () that prevented it from fulfilling this request.

exception

javax.servlet.ServletException: Servlet execution threw an exception


root cause

java.lang.ExceptionInInitializerError
      sun.reflect.NativeConstructorAccessorImpl.newInstance0(Native Method)
      sun.reflect.NativeConstructorAccessorImpl.newInstance(NativeConstructorAccessorImpl.java:39)
      sun.reflect.DelegatingConstructorAccessorImpl.newInstance(DelegatingConstructorAccessorImpl.java:27)
      java.lang.reflect.Constructor.newInstance(Constructor.java:494)
      java.lang.Class.newInstance0(Class.java:350)
      java.lang.Class.newInstance(Class.java:303)
      org.apache.struts.util.RequestUtils.applicationInstance(RequestUtils.java:143)
      org.apache.struts.action.RequestProcessor.processActionCreate(RequestProcessor.java:280)
      org.apache.struts.action.RequestProcessor.process(RequestProcessor.java:218)
      org.apache.struts.action.ActionServlet.process(ActionServlet.java:1196)
      org.apache.struts.action.ActionServlet.doPost(ActionServlet.java:432)
      javax.servlet.http.HttpServlet.service(HttpServlet.java:709)
      javax.servlet.http.HttpServlet.service(HttpServlet.java:802)

------------------------------------------------------------------------------------
I have initialized in my action class(LoginAction)

package com.yourcompany.struts;

import java.util.ArrayList;

import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;

import org.apache.struts.action.*;
import org.apache.log4j.Logger;

public class LoginAction extends Action{
      
      public static int i;
      private static final Logger logger= Logger.getLogger(ActionForm.class);
      
      public ActionForward execute(ActionMapping mapping,ActionForm form,HttpServletRequest request,HttpServletResponse response) throws java.lang.Exception
      {
          logger.debug("->> Execute");
            LoginForm frm= (LoginForm)form;
            NameclassService ncs;
            
            ArrayList name_list=frm.getTotal_name();
            
            ncs= new NameclassService();
                  
            
            ncs.setLoginForm(frm);
            name_list=(ArrayList)ncs.fetchName();
            
            frm.setTotal_name(name_list);
            return mapping.findForward("success");
            
      }

}

----------------------------------------------------------------
also I am getting warnings while starting server..................
log4j:WARN No appenders could be found for logger (org.apache.catalina.session.ManagerBase).
log4j:WARN Please initialize the log4j system properly.

Pls Help...

Dojjol
0
Comment
Question by:dojjol
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7 Comments
 
LVL 16

Expert Comment

by:suprapto45
ID: 17825750
I think that you have to set the log4j.properties somewhere.

http://forum.java.sun.com/thread.jspa?threadID=404853&start=0
0
 
LVL 10

Expert Comment

by:jaggernat
ID: 17826037
use this code from my project


If you want to create log files using log4j, there is a certain programming structure you have to follow like this


+++++++++++++++++
import java.io.File;

import org.apache.log4j.Level;
import org.apache.log4j.Logger;
import org.apache.log4j.PatternLayout;
import org.apache.log4j.Priority;
import org.apache.log4j.RollingFileAppender;

private Logger standardLogger;
String loggerName = "MyProjectLogger";
File standardlogPath = new File(standardLogFilePath);
//standardLogFilePath  is directory where you want the log files to be stored. so   standardLogFilePath=c:/logfiles
if (!standardlogPath.exists()) {
standardlogPath.mkdirs();   //if directory doesnt exist , create one
}

PatternLayout layout =
new PatternLayout(PatternLayout.TTCC_CONVERSION_PATTERN);
layout = new PatternLayout("%d - %p - %m%n");
//PatternLayout  is a predefined class provided by log4j

RollingFileAppender fileAppender1 = new RollingFileAppender();
//RollingFileAppender is a predefined class provided by log4j package
fileAppender1 = new RollingFileAppender(layout, standardLogFilePath + standardLogFileName,
true);


//standardLogLevel is the log level which you have to set based on your project requirments.It can be debug,info,warn,error or fatal
//check for standardLogLevel conditions and set threshhold(Priority ) accordingly

if (standardLogLevel.equals("DEBUG")) {
fileAppender1.setThreshold(Priority.DEBUG);
} else if (standardLogLevel.equals("INFO")) {
fileAppender1.setThreshold(Priority.INFO);
} else if (standardLogLevel.equals("WARN")) {
fileAppender1.setThreshold(Priority.WARN);
} else if (standardLogLevel.equals("ERROR")) {
fileAppender1.setThreshold(Priority.ERROR);
} else if (standardLogLevel.equals("FATAL")) {
fileAppender1.setThreshold(Priority.FATAL);
}

standardLogger = Logger.getLogger(loggerName);
standardLogger.addAppender(fileAppender1);
//you have to use above line, that is why you are getting error No appenders found!
            }
0
 

Author Comment

by:dojjol
ID: 17826597
>>I think that you have to set the log4j.properties somewhere.
I have already set Log4J.properties under WEB-INF/classes folder as I am using Tomcat...
It is not helping..

I want to use Log4J utility thru properties file...
Is it really neccsary to write a class for intializing logger....as tomcat automatically intiliazes Log4J.properties when kept under WEB-INF/classes folder

Pls suggest

Regards,
dojjol
0
 
LVL 10

Expert Comment

by:jaggernat
ID: 17826693
>>Is it really neccsary to write a class for intializing logger

you dont have to.

Just make sure you have everything setup properly in the log4j.properties file. make sure you have these in it

log4j.rootLogger=info, A
log4j.appender.A=org.apache.log4j.ConsoleAppender
log4j.appender.A.layout=org.apache.log4j.PatternLayout
log4j.appender.A.layout.ConversionPattern=%-4r [%t] %-5p %c %x - %m%n


 
0
 
LVL 10

Accepted Solution

by:
jaggernat earned 2000 total points
ID: 17826703
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