triple integral in spherical coordinates
Posted on 2006-10-28
Consider the following triple integral:
/ 2pi / pi / sqrt(2)
| | | f(p,x,y) p^2 sin y dp dx dy
| | |
/ 0 / 3pi/4 /0
Where p is rho, x is phi, y is theta in spherical coordinates. I'm trying to convert this integral to cartesian coordinates.
Its rather easy to see that the outer most integral will have limits of (-sqrt(2) to sqrt(2)) with respect to x, the middle integral will have limits of (-sqrt(2 - x^2) to sqrt(2 - x^2)) with respect to y, my problem is the inner most integral with respect to z. The book has the answer as something like -sqrt(2 - x^2 - y^2) to sqrt(x^2 + y^2). I'm just not seeing where this is coming from.