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Regular Expression for UK phone number.

Posted on 2006-10-30
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Last Modified: 2010-08-13
I am trying to develop a Regular Expression to validate a UK telophone number, with the following criteria:
* The entry must start with a zero.
* Numbers or spaces only.
* Cannot enter less than 10 or more than 15 numbers.
Ie. valid:

01865 215487
01865215487
020 3265 9854

This was my attempt but its not quite right:

      var regex = /^0\d{4}(\s{0,1})\d{6}$/
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Question by:jonatec
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Accepted Solution

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callrs earned 1000 total points
ID: 17832313
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Expert Comment

by:callrs
ID: 17887420
Thanks.  Code for reference:

<script type="text/javascript">
<!-- Verify UK Phone number -->

var rx1 = /^0\d{4}\s?\d{6}$/
var rx2 = /^0\d{2}\s?\d{4}\s?\d{4}$/
var rx3 = /^0\d{10,15}$/

// test for rx1 and rx2 patterns
var p=new Array("01865 215487","01865215487","020 3265 9854","01234 5678 9012 34","0ab123457890");
var o="";
for (i=0; i<p.length; i++){
      var tested=rx1.test(p[i])
      if(!tested) tested=rx2.test(p[i])
      o=o+p[i]+": "+tested+"\n"
      }
alert(o);

// test for rx3, after trimming out spaces
o="After trimming spaces to allow for 10 to 15 digits\n";
for (i=0; i<p.length; i++){
      var newp=p[i].replace(/\s*/g,"");
      var tested=rx3.test(newp)
      o=o+p[i]+": "+tested+"\n"
      }
alert(o);

</script>
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