Solved

find all possible sequence value from a matrix

Posted on 2006-10-30
1
181 Views
Last Modified: 2012-05-05
hi,


 | a     |   b     |     c     |
---------------------------------|
a| 0.5  | 0.25   | 0.25    | =1
---------------------------------|    
b| 0.375| 0.125 | 0.375  | =1
---------------------------------|
c| 0.125| 0.675 | 0.375  | =1
-----------------------------------


I need calculate the probability from a above matrix

for example, if I want to find a sequence of aab, it should calculate like:
a-->a-->b = 0.5 * 0.25 = 0.125

could someone give me some codes to find "all possible paths" for any given sequence? for example for sequence of 3, there is 3^3=27 possible paths (aaa,aab,aac, aba....ccc.etc). I want to find the probability of all 27 paths.
0
Comment
Question by:rmtogether
[X]
Welcome to Experts Exchange

Add your voice to the tech community where 5M+ people just like you are talking about what matters.

  • Help others & share knowledge
  • Earn cash & points
  • Learn & ask questions
1 Comment
 
LVL 11

Accepted Solution

by:
Expert1701 earned 500 total points
ID: 17838934
The following code,

  double[,] matrix = new double[,] { { 0.5, 0.25, 0.25 }, { 0.375, 0.125, 0.375 }, { 0.125, 0.675, 0.375 } };
  System.Diagnostics.Debug.Assert(matrix.GetLength(0) == matrix.GetLength(1));

  int sequences = 3;

  for (int i = 0; i < (int)Math.Pow(matrix.GetLength(0), sequences); i++)
  {
    double p = 1;
   
    Console.Write((char)('a' + ((i / (int)Math.Pow(matrix.GetLength(0), 0)) % matrix.GetLength(0))));

    for (int j = 1; j < sequences; j++)
    {
      int a = (i / (int)Math.Pow(matrix.GetLength(0), j - 1)) % matrix.GetLength(0);
      int b = (i / (int)Math.Pow(matrix.GetLength(0), j)) % matrix.GetLength(0);
      p *= matrix[a, b];

      Console.Write("->" + (char)('a' + b));
    }

    Console.WriteLine(" " + p);
  }

  Console.ReadLine();

produces the output ("a->a->b 0.125"),

a->a->a 0.25
b->a->a 0.1875
c->a->a 0.0625
a->b->a 0.09375
b->b->a 0.046875
c->b->a 0.253125
a->c->a 0.03125
b->c->a 0.046875
c->c->a 0.046875
a->a->b 0.125
b->a->b 0.09375
c->a->b 0.03125
a->b->b 0.03125
b->b->b 0.015625
c->b->b 0.084375
a->c->b 0.16875
b->c->b 0.253125
c->c->b 0.253125
a->a->c 0.125
b->a->c 0.09375
c->a->c 0.03125
a->b->c 0.09375
b->b->c 0.046875
c->b->c 0.253125
a->c->c 0.09375
b->c->c 0.140625
c->c->c 0.140625
0

Featured Post

Industry Leaders: We Want Your Opinion!

We value your feedback.

Take our survey and automatically be enter to win anyone of the following:
Yeti Cooler, Amazon eGift Card, and Movie eGift Card!

Question has a verified solution.

If you are experiencing a similar issue, please ask a related question

Summary: Persistence is the capability of an application to store the state of objects and recover it when necessary. This article compares the two common types of serialization in aspects of data access, readability, and runtime cost. A ready-to…
Entity Framework is a powerful tool to help you interact with the DataBase but still doesn't help much when we have a Stored Procedure that returns more than one resultset. The solution takes some of out-of-the-box thinking; read on!
There are cases when e.g. an IT administrator wants to have full access and view into selected mailboxes on Exchange server, directly from his own email account in Outlook or Outlook Web Access. This proves useful when for example administrator want…
Monitoring a network: why having a policy is the best policy? Michael Kulchisky, MCSE, MCSA, MCP, VTSP, VSP, CCSP outlines the enormous benefits of having a policy-based approach when monitoring medium and large networks. Software utilized in this v…

729 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question