Want to win a PS4? Go Premium and enter to win our High-Tech Treats giveaway. Enter to Win

x
?
Solved

args not working in if statement

Posted on 2006-10-30
3
Medium Priority
?
274 Views
Last Modified: 2012-05-05
I want to check when the user has entered in a question mark (or "/?" or "-?") as an argument.
This is my code:

if (args[0] == "/?" || args[0] == "-?" || args[0] == "?") {
   System.out.println("help stuff")
}

I passed "/?" as an argument and nothing happened. I added some debugging code:

System.out.println(args[0]);
if (args[0] == "/?" || args[0] == "-?" || args[0] == "?") {
   System.out.println("help stuff")
} else {
   System.out.println("this text shouldnt be printed");
}

Once again I pass "/?" as an argument and get back:
/?
this text shouldnt be printed

Please help me.
Thanks in advance.

0
Comment
Question by:snowy0
[X]
Welcome to Experts Exchange

Add your voice to the tech community where 5M+ people just like you are talking about what matters.

  • Help others & share knowledge
  • Earn cash & points
  • Learn & ask questions
  • 3
3 Comments
 
LVL 86

Expert Comment

by:CEHJ
ID: 17838097
>>if (args[0] == "/?" || args[0] == "-?" || args[0] == "?") {


should be


if ("//?".equals(args[0] ....................................................
0
 
LVL 86

Accepted Solution

by:
CEHJ earned 500 total points
ID: 17838099
Sorry

if ("/?".equals(args[0] ....................................................
0
 
LVL 86

Expert Comment

by:CEHJ
ID: 17840395
:-)

You could also do

if (args[0].matches("[/\\-]*\\?"))
0

Featured Post

Free Tool: Port Scanner

Check which ports are open to the outside world. Helps make sure that your firewall rules are working as intended.

One of a set of tools we are providing to everyone as a way of saying thank you for being a part of the community.

Question has a verified solution.

If you are experiencing a similar issue, please ask a related question

In this post we will learn how to make Android Gesture Tutorial and give different functionality whenever a user Touch or Scroll android screen.
Basic understanding on "OO- Object Orientation" is needed for designing a logical solution to solve a problem. Basic OOAD is a prerequisite for a coder to ensure that they follow the basic design of OO. This would help developers to understand the b…
Viewers will learn about arithmetic and Boolean expressions in Java and the logical operators used to create Boolean expressions. We will cover the symbols used for arithmetic expressions and define each logical operator and how to use them in Boole…
This tutorial covers a practical example of lazy loading technique and early loading technique in a Singleton Design Pattern.
Suggested Courses

618 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question