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Batch file add a parameter
my batch file:ungz.bat
c:\share\pacl\paext -p"c:\share\archive" c:\share\winzip100.exe.gz
del c:\share\winzip100.exe.gz
I call it with CMD c:\share\ungz.bat
I want to pass it a filename:
call it with CMD c:\share\unzip.bat myfile.gz
and have it do this:
c:\share\pacl\paext -p"c:\share\archive" c:\share\myfile.gz
del c:\share\mfile.gz
c:\share\pacl\paext -p"c:\share\archive" c:\share\winzip100.exe.gz
del c:\share\winzip100.exe.gz
I call it with CMD c:\share\ungz.bat
I want to pass it a filename:
call it with CMD c:\share\unzip.bat myfile.gz
and have it do this:
c:\share\pacl\paext -p"c:\share\archive" c:\share\myfile.gz
del c:\share\mfile.gz
Asked:
2-
2
1 Solution
%1 would be the first parameter of a batch file, %2 is the 2nd, etc.
So if I understand your question, I think you want your batch file to be:
c:\share\pacl\paext -p"c:\share\archive" %1
del %1
So if I understand your question, I think you want your batch file to be:
c:\share\pacl\paext -p"c:\share\archive" %1
del %1
so this?
@echo off
::ungz.bat
::Usage command [command parameters]
REM This script decompresses gz files and puts them in the achive
c:\share\pac\paext -p"c:\share\archive" %1
del c:\share\ %1
:EOF
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for instance the first parameter would be assigned %1
Example:
c:\share\pac\paext -p"c:\share\archive" %1