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XSLT: Convert Character entity to hex

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Last Modified: 2013-11-18
Hello,
I am trying to use  XSLT to convert character entities to hex. I am using Xalan/Xerces.

Example:-  ’ -> ’

Please suggest.

Thanks,
Kanishk.
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Commented:
Hmm, I don't think it can be done with pure XSLT, but I am interested to hear what others have to say.
I'm pretty certain you can't do that in XSLT ... though Xerces does allow for callback functions which you might be able to use.

If you treat the XML as a string you could iterate over every character and easily replace those which need replacing though.

Author

Commented:
ohk.
I can use java's replaceAll method to get the job done. but I wanted a bit more scalable approach so that we don't have to rebuild the code incase a new special character is needed.
Any other suggestions? :)
Use a generic replacement method that will replace any char over #159 with &#ord(char);

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Gertone (Geert Bormans)Information Architect
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Top Expert 2006

Commented:
Stream through your text nodes using a java function is about the best option you have
you can implement the entire character map in your java function,
then it would be scalable

If XSLT2.0 and Saxon instead of Xalan were an option,
it might be worthwhile looking at xsl:character-map

don't go recursing through your data using XSLT1 named templates.
You could do that... but here is the time that you should step outside with an extension function

Author

Commented:
I can use XSLT 2.0 and Saxon, if needed. Can I get some directions on that?
Gertone (Geert Bormans)Information Architect
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Top Expert 2006
Commented:
first you need to create a character map

<xsl:output use-character-maps="my_map"/>

<xsl:character-map name="my_map">
     <xsl:output-character char="’" string="&amp;#8217;"/>
     <xsl:output-character char="......
</character-map>

you can add as many output characters as you please

character maps apply to the whole document

That is all there is to it

cheers

Geert
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