?
Solved

replacement of 'document.all' for netscape 6 or firefox

Posted on 2006-11-02
3
Medium Priority
?
179 Views
Last Modified: 2011-09-20
i read from the web that document.all is not supported for netscape 6. is there a way to find out the object width regardless of the browser used by the client?
My current codes are:
document.all.item(aBoxes[i]).style.pixelLeft
but i cant use in for netscape 6
0
Comment
Question by:wisecat83
[X]
Welcome to Experts Exchange

Add your voice to the tech community where 5M+ people just like you are talking about what matters.

  • Help others & share knowledge
  • Earn cash & points
  • Learn & ask questions
3 Comments
 
LVL 20

Accepted Solution

by:
hes earned 120 total points
ID: 17866474
Try
document.getElementById("dwindow").style.width
0

Featured Post

On Demand Webinar: Networking for the Cloud Era

Ready to improve network connectivity? Watch this webinar to learn how SD-WANs and a one-click instant connect tool can boost provisions, deployment, and management of your cloud connection.

Question has a verified solution.

If you are experiencing a similar issue, please ask a related question

Go is an acronym of golang, is a programming language developed Google in 2007. Go is a new language that is mostly in the C family, with significant input from Pascal/Modula/Oberon family. Hence Go arisen as low-level language with fast compilation…
This article is meant to give a basic understanding of how to use R Sweave as a way to merge LaTeX and R code seamlessly into one presentable document.
This theoretical tutorial explains exceptions, reasons for exceptions, different categories of exception and exception hierarchy.
The viewer will learn how to user default arguments when defining functions. This method of defining functions will be contrasted with the non-default-argument of defining functions.
Suggested Courses

770 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question