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c++ substring to char

Posted on 2006-11-03
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2,190 Views
Last Modified: 2008-01-09
Okay I want to take a single char from a sting and place into a char variable.
Heres my current code:

//The convert function takes a string of numbers and returns its integer value.
int convert(string strNum)
{
      char c;
      const int Size = strNum.size();
      int I;
      int J;
      int X;
      int Y;
      int total;
      int tmpint1;
      int tmpint2;
      const int plusone = Size + 1;
      
      for(I = 1; I < plusone; I++)
      {
            X = Size - I;
            if (X > 0)
            {
                  Y = 10;
                  for(J = 1; J < X; J++)
                  {
                        Y = Y * 10;
                  }
            }
            else Y = 1;
            c = strNum.substr(I,I);
            tmpint1 = c - '0';
            tmpint2 = tmpint1 * Y;
            total = total + tmpint2;
      }
      return total;
}

The only error with it is:

sr1 $ CC -o Program08 Program08.cpp
"Program08.cpp", line 182: Error: Cannot assign std::string  to char.
1 Error(s) detected.

How could I fix this?
0
Comment
Question by:xneo27
[X]
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7 Comments
 
LVL 5

Expert Comment

by:rmahesh
ID: 17868608
This should work:

c = strNum.at(I);

Mahesh
0
 
LVL 5

Expert Comment

by:rmahesh
ID: 17868656

But I believe that you want to do this conversion yourself for some reason.

Hope you know "atoi" and related functions doing the same.
0
 

Author Comment

by:xneo27
ID: 17868759
is there any other way to do it, see I dont think that I am allowed to use either of those methods
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LVL 4

Expert Comment

by:hclgroup
ID: 17868850
Why not just use builtin c++ functions to do your convertion

e.g.

#include <stdlib.h>

atoi(strNum.c_str());
0
 
LVL 5

Expert Comment

by:rmahesh
ID: 17869017
You should just be able to call atoi ... ( atoi(strNum.c_str()); )  whats the error you get when u try to call?
0
 
LVL 4

Expert Comment

by:chhokra_expert
ID: 17871339
if it is a c++ string, you can simply do c = strNum[i] where string::size_type i = 0; i < strNum.length(); ++i
strNum.at(i) is its functional equivalent
0
 
LVL 2

Accepted Solution

by:
Ehsan_Noureddin earned 500 total points
ID: 17885943
chhokra_expert is correct. if you have string why you use these code ?!
but here i will write you the function for changing the String to Integer :

int String_to_Integer(char *s)
{
      int value=0;
      while (*s)
      {
            value*=10;
            value+=*s-48;          // Or you can use : value+=*s-'0';
            s++;
      }
      return value;
}

this function will convert the string to Integer (just Integer not Float) .
you can use this
0

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