We help IT Professionals succeed at work.

We've partnered with Certified Experts, Carl Webster and Richard Faulkner, to bring you two Citrix podcasts. Learn about 2020 trends and get answers to your biggest Citrix questions!Listen Now

x

urllib2 info()

bnblazer
bnblazer asked
on
Medium Priority
1,100 Views
Last Modified: 2011-09-20
Sorry if this is a stupid question, but I am a bit stuck.  I am using info() from urllib2.  It returns the metadata of the url.  I would like to print 'some' of this info to the screen, but I can't seem to get just what I want.  I would like to avoid re, but am prepared to use it if needed.

For example.  Calling info() on cnn.com produces this output:

ate: Sat, 04 Nov 2006 00:01:09 GMT
Server: Apache
Vary: Accept-Encoding,User-Agent
Cache-Control: max-age=60, private
Expires: Sat, 04 Nov 2006 00:02:01 GMT
Content-Type: text/html
Content-Length: 103933
Connection: close

How would I just get parts of it?  For example, just the Server and content-type.  Or the content length, expiration and ate?  I believe that info() returns a dict, but I am not sure.

Thanks,
Brian
Comment
Watch Question

Commented:
info() actually returns an httplib.HTTPMessage.

http://doc.astro-wise.org/httplib.html#HTTPMessage

You can use the get function of the HTTPMessage to get any header by name.

>>> import urllib2
>>> response = urllib2.urlopen("http://www.experts-exchange.com/Programming/Programming_Languages/Python/Q_22048712.html")
>>> info = response.info()
>>> info.get("Server")
'Apache-Coyote/1.1'

Not the solution you were looking for? Getting a personalized solution is easy.

Ask the Experts

Author

Commented:
Thank you!

Brian
Access more of Experts Exchange with a free account
Thanks for using Experts Exchange.

Create a free account to continue.

Limited access with a free account allows you to:

  • View three pieces of content (articles, solutions, posts, and videos)
  • Ask the experts questions (counted toward content limit)
  • Customize your dashboard and profile

*This site is protected by reCAPTCHA and the Google Privacy Policy and Terms of Service apply.

OR

Please enter a first name

Please enter a last name

8+ characters (letters, numbers, and a symbol)

By clicking, you agree to the Terms of Use and Privacy Policy.