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Didnt see Ozo'as post while posting<br />
<br />
<a href="http://farside.ph.utexas.edu/teaching/302l/lectures/node43.html" rel="ugc">http://farside.ph.utexas.edu/teaching/302l/lectures/node43.html</a>
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Didnt see Ozo'as post while posting

http://farside.ph.utexas.edu/teaching/302l/lectures/node43.html [http://farside.ph.utexas.edu/teaching/302l/lectures/node43.html]

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Ozo, I hope by IR, yo umeant internal resistance and not I*R. Could be intereprested both ways. 
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Ozo, I hope by IR, yo umeant internal resistance and not I*R. Could be intereprested both ways.

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actually both showed up at the same time..<br />
thanks gentlemen..<br />
<br />
thanks ozo!
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actually both showed up at the same time..
thanks gentlemen..

thanks ozo!

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<div class="content wysiwyg-content">
when an external resistor R1=14 is connected to the terminals of the battery , a current of I=6 flows through the resistor. when an external resistor of R=64.4 is connected instead, the current is 2. Calculate the <br />
emf of the battery and the internal resistance of the battery<br />
<br />
solution that i tried:<br />
<br />
for emf : &nbsp;emf = Vab = IR &nbsp;6*14<br />
<br />
internal resistance should be &nbsp;Vab= Emf-I*R and solve for R , <br />
<br />
am i right??
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when an external resistor R1=14 is connected to the terminals of the battery , a current of I=6 flows through the resistor. when an external resistor of R=64.4 is connected instead, the current is 2. Calculate the 
emf of the battery and the internal resistance of the battery

solution that i tried:

for emf :  emf = Vab = IR  6*14

internal resistance should be  Vab= Emf-I*R and solve for R , 

am i right??

calculate EMF of Battery

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