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# calculate EMF of Battery

Posted on 2006-11-03
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when an external resistor R1=14 is connected to the terminals of the battery , a current of I=6 flows through the resistor. when an external resistor of R=64.4 is connected instead, the current is 2. Calculate the
emf of the battery and the internal resistance of the battery

solution that i tried:

for emf :  emf = Vab = IR  6*14

internal resistance should be  Vab= Emf-I*R and solve for R ,

am i right??
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Question by:c_hockland
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LVL 84

Accepted Solution

ozo earned 400 total points
ID: 17871812
emf/(14+IR)=6
emf/(64.4+IR)=2
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LVL 16

Assisted Solution

manav_mathur earned 100 total points
ID: 17871815
E = 6*(r + 14)
E = 2*(r+64.4)

there are 2 equations and 2 unknowns. Solve for E & r.
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LVL 16

Expert Comment

ID: 17871817
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LVL 16

Expert Comment

ID: 17871819
Ozo, I hope by IR, yo umeant internal resistance and not I*R. Could be intereprested both ways.
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Author Comment

ID: 17871821
actually both showed up at the same time..
thanks gentlemen..

thanks ozo!
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