when an external resistor R1=14 is connected to the terminals of the battery , a current of I=6 flows through the resistor. when an external resistor of R=64.4 is connected instead, the current is 2. Calculate the
emf of the battery and the internal resistance of the battery
solution that i tried:
for emf : emf = Vab = IR 6*14
internal resistance should be Vab= Emf-I*R and solve for R ,
am i right??