value of magnetic field

Posted on 2006-11-03
1 Endorsement
Last Modified: 2006-11-18
A coaxial cable consists of an inner cylindrical conductor of Radius R1=0.040m on the axis of an outer hollow cylindrical conductor of inner radius R2=0.080m and outer radius=0.090m. The inner conductor carries current  I2=1 A in one direction and the outer carries I2=5A in the opposite direction. What is the value of the magnetic field at the following distances from the axis of the cable ?
a) at  r=0.060m (in the gap midway the two conductors ) ?
b) at r=0.150m (outside the cable ) ?

Note U0=4pi *10^(-7) A

ANy ideas??
Question by:c_hockland
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Expert Comment

ID: 17872249
The field at r=0.060m  depends only on r and the current on the inner conductor
the field at r=0.150m depends only on r and the sum of the currents in both conductors.
LVL 84

Expert Comment

ID: 17872257

Author Comment

ID: 17872262
ok Ozo , let me work on it really quick and get back shall i get stuck...
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Author Comment

ID: 17873727
ok ,thus for a)

B=4*pi*1 / 2*3,14*0.060

and for question b)  

B= 4*pi*5 / 2*3.14 * 0.150

did i get it right ?

LVL 84

Accepted Solution

ozo earned 500 total points
ID: 17874508
The two conductors carry current in oposite directions, so what is the net current of the total?

Author Comment

ID: 17874513
so net current should be I1-I2 = 4 A


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