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value of magnetic field

c_hockland
c_hockland asked
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Last Modified: 2006-11-18
A coaxial cable consists of an inner cylindrical conductor of Radius R1=0.040m on the axis of an outer hollow cylindrical conductor of inner radius R2=0.080m and outer radius=0.090m. The inner conductor carries current  I2=1 A in one direction and the outer carries I2=5A in the opposite direction. What is the value of the magnetic field at the following distances from the axis of the cable ?
a) at  r=0.060m (in the gap midway the two conductors ) ?
b) at r=0.150m (outside the cable ) ?

Note U0=4pi *10^(-7) A

ANy ideas??
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ozo
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Most Valuable Expert 2014
Top Expert 2015

Commented:
The field at r=0.060m  depends only on r and the current on the inner conductor
the field at r=0.150m depends only on r and the sum of the currents in both conductors.
ozo
CERTIFIED EXPERT
Most Valuable Expert 2014
Top Expert 2015

Commented:

Author

Commented:
ok Ozo , let me work on it really quick and get back shall i get stuck...

Author

Commented:
ok ,thus for a)

B=4*pi*1 / 2*3,14*0.060

and for question b)  

B= 4*pi*5 / 2*3.14 * 0.150

did i get it right ?

CERTIFIED EXPERT
Most Valuable Expert 2014
Top Expert 2015
Commented:
The two conductors carry current in oposite directions, so what is the net current of the total?

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Author

Commented:
so net current should be I1-I2 = 4 A

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