Add an item to a listbox in another running process

Posted on 2006-11-04
Medium Priority
Last Modified: 2010-04-05
I have a running process (not my own) and I want to add an item to a listbox.

I have the handle of the listbox control, can somebody give me some code to add an item to it?

Question by:zattz
  • 3
LVL 28

Accepted Solution

TName earned 2000 total points
ID: 17873837
Hi, do you mean something like this? It will insert a string (as last item) into a listbox:

procedure TMainForm.Button1Click(Sender: TObject);
 if hnd<>0 then begin
   hnd := FindWindowEx(hnd, 0, 'TListBox', nil);
   if hnd<>0 then begin
      Count:=SendMessage(hnd, LB_GETCOUNT,0,0);
      SendMessage(hnd, LB_INSERTSTRING,Count-1,Integer(pc));
LVL 28

Expert Comment

ID: 17873852
Oops, sorry, if it's supposed to be the last item, it should be:

SendMessage(hnd, LB_INSERTSTRING,Count,Integer(pc));
LVL 26

Expert Comment

by:Russell Libby
ID: 17873921
Yep... one of the few exceptions where you can send(message) a string to a remote process without first allocating memory in the remote process. You can also just pass (-1) as the index if you want to append to the list (no need to get count)

LVL 28

Expert Comment

ID: 17874632
>You can also just pass (-1) as the index if you want to append to the list (no need to get count)

Thanks, I wasn't aware of that :)

And I just see there's also LB_ADDSTRING.
So zattz, in fact if you already have the LB handle, all you really need is a line like:
SendMessage(hnd, LB_INSERTSTRING,-1,Integer(PChar('TestString')));

SendMessage(hnd, LB_ADDSTRING,0,Integer(PChar('TestString')));


Author Comment

ID: 17876188
Thanks Guys:)

Worked perfectly.

Except that I made a mistake and actually wanted to send to a combobox so I changed LB_ADDSTRING to CB_ADDSTRING


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