Go Premium for a chance to win a PS4. Enter to Win

x
?
Solved

Letter Frequency Histogram

Posted on 2006-11-05
5
Medium Priority
?
970 Views
Last Modified: 2012-05-05
Hi , Does any one know of an example or tutorial of how to print a letter frequency histogram using a string phrase or word? Where only the letters used in the string would on the vertical axis and each letter's frequency would be represented by a certain character?
0
Comment
Question by:wkellya
  • 2
  • 2
5 Comments
 
LVL 85

Expert Comment

by:ozo
ID: 17878583
0
 

Author Comment

by:wkellya
ID: 17879981
Thanks, but I need something like

string= Deed

    1 2 3 4 5
d|**
e|**

1)How do I hide the letters not in the string a-z?
2)can this be done in a function that accepts string as a parameter?
0
 
LVL 24

Expert Comment

by:fridom
ID: 17880614
Well that's not too difficult if you spend some time thinking about it. You better uses some array then while displaying the result you check the content of this array. In C this might look like:

enum {MAX_ALPHABET_NUM=26};
char alphabet[MAX_ALPHABET_NUM] = {0};

for (int i = 0; i < MAX_ALPHABET_NUM; i++) {
   if (alphabet[i] > 0)
      // print the line
....

So with that both question are mostly answered.

Regards
Friedrich
0
 

Author Comment

by:wkellya
ID: 17881495
say I have a string
char string[80];

can i print it like

printf("%13s%13s%13s%13s%13s\n","10","20","30","40","50");
      for(int k=0;k<80;k++){
            printf("%7c%13c%      ",k,string[k]);

            for (int l=1; l<=string[i];l++){
                  printf("%c",'*');
            }
            printf("\n");
      }

but count each letter?
0
 
LVL 24

Accepted Solution

by:
fridom earned 750 total points
ID: 17882304
You have not assigned string any value, and you do not have any array to hole the counter for the number of characters.

So let's assume string[80] = "foobarbaz";
and you have int alphabet[26] = {0};
alphabet[0] contains the counters for the 'a's.

then you can fill the array this way (not tested just written from memory)

size_t str_len = strlen(string);

for (int i = 0; i < str_len; i++) {
   char ch = string[i];
   alphabet[tolower(ch) - 'a']++;
}

Then after going through string you have the numbers collected in alphabet

You then can print it as you like
ch = 'a';
for (int i = 0; i < 26 ; i++){
    printf("%c occurs %d times\n", ch, alphabet[i]);
    ch++;
}


Regards
Friedrich


 
0

Featured Post

Industry Leaders: We Want Your Opinion!

We value your feedback.

Take our survey and automatically be enter to win anyone of the following:
Yeti Cooler, Amazon eGift Card, and Movie eGift Card!

Question has a verified solution.

If you are experiencing a similar issue, please ask a related question

An Outlet in Cocoa is a persistent reference to a GUI control; it connects a property (a variable) to a control.  For example, it is common to create an Outlet for the text field GUI control and change the text that appears in this field via that Ou…
Windows programmers of the C/C++ variety, how many of you realise that since Window 9x Microsoft has been lying to you about what constitutes Unicode (http://en.wikipedia.org/wiki/Unicode)? They will have you believe that Unicode requires you to use…
Video by: Grant
The goal of this video is to provide viewers with basic examples to understand and use nested-loops in the C programming language.
The goal of this video is to provide viewers with basic examples to understand opening and reading files in the C programming language.

916 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question