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Sorting Strings Numerically

yourbudweiser
on
Medium Priority
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Last Modified: 2013-12-09
I have a field in my database that I need to sort. The field is a string but I need to sort numerically.

Version=9.5;Prior=NONE;
Version=9.2a;Prior=NONE;
Version=13.3;Prior=USS;
Version=13.1b;Prior=UAN;

How can I grab the version number and sort it so instead of:

9.5
9.2a
13.3
13.1b

I get:

13.3
13.1b
9.5
9.2

Someone suggested to me:

OK, here's one way...

Example "Builds" table:

Build
------
9.5
9.2a
13.3
13.1b
2.0
2.0a
2.0b
2.1
2.1a
2.1b

Querying the Builds table, sorting by the major build value:

SELECT
     Build,
     CAST(PARSENAME(Build,2) AS INT) AS MajorVersion,
     PARSENAME(Build,1) AS MinorVersion
FROM Builds
ORDER BY MajorVersion, MinorVersion

Outputs the following:

Build      MajorVersion MinorVersion
---------- ------------ ------------
2.0        2            0
2.0a       2            0a
2.0b       2            0b
2.1        2            1
2.1a       2            1a
2.1b       2            1b
9.2a       9            2a
9.5        9            5
13.1b      13           1b
13.3       13           3

I am using Firebird not SQL Server.

I am low on points but need help please. Thanks!
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Nick UpsonPrincipal Operations Engineer
CERTIFIED EXPERT

Commented:
what version of firebird are you using?

Author

Commented:
Hi NickUpson, we are using Firebird 1.5
Nick UpsonPrincipal Operations Engineer
CERTIFIED EXPERT

Commented:
I don't have time to write the code but I can give you the information necessary for you to do it

create an additional field in the table to hold the numeric form, say vernum
write an stored procedure that uses substring to step through the field, 1 char at a time until hits a non-numeric (skip/handle decimal point) building up the numeric form and save it.
then select and sort by the numeric form

if you are going to need it again, put the code in an trigger so that vernum is kept updated as data is updated/inserted

Author

Commented:
that is the general idea I received above but I am not sure how to extract just the version number from the string and I am not experienced to write stored procedures. Is there no quick and dirty way to do this in the sql statement?

Version=9.7;PriorCompany=NONE;Password=123abc;userName=JAZARETPC;testServer=ONLINE;
Principal Operations Engineer
CERTIFIED EXPERT
Commented:
there is no quick & dirty way as the position & length of the part you want varies

if it was in the same place you could do it, you need something like

for select ... into ... :myvar
do
begin
  i = 0;
  vernum = 0;
  while (substr(myvar, i, 1) < '0' and substr(myvar, i, 1) > '9')
    vernum = (varnum * 10) + substr(myvar, i, 1)
  update mytable set vernum = :vernum where ...
end

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Author

Commented:
thanks for the help, this is too comlicated for me as I cannot modify the database by adding stored procedures or additional fields in the table. Thanks for taking a look though.
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