Finding a bash script's full path

I'm wondering if any experts in bash could offer me a better way to computer the full pathname to $0 in a script.

Specifically, I need to know the path the script is in, so it can do it's work in that (and only in that) directory.

Right now, I'm using the following four lines:
DIR="$PWD/`dirname $0`"      #Compute a full path name to this script
DIR=${DIR%.}            #Strip off trailing period
DIR=${DIR%\/}            #Strip off trailing slash
DIR=${DIR/\/\/\//\/}#Reduce any initial /// to /

The first line creates a full path, but it may have some strangeness (e.g., a trailing period if the bash script is launched directly from the directory, the odd trailing "/" in some cases, and the problem of "///home/xyz/abc", which $PWD can produce.

This four-line sequence works; I'm interesting in finding out of there any easier way to do this for my future bash scripts
Who is Participating?
ozoConnect With a Mentor Commented:
dirname `which $0`
which $0
CAOgdinAuthor Commented:
Nice one.  I wonder how it missed that command.

Still not quite there, though.  I need it without the name of the script...just the path to the script itself.

It returns /home/xyz/abc/test for a script named "test."  I need just /home/xyz/abc
CAOgdinAuthor Commented:
Slick!  I'm impressed (and it urges me on to learn more about bash).

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