How to resolve an error where a table that is contained in a defined dataset is not a member of System.Data.Dataset

I'm experiencing a problem where I'm attempting to use a table that is defined to a dataset, yet receiving an error message indicating that the table is not part of System.Data.Dataset.  Below please find the code snippet that is generating the error:

    Dim cmdACSelect As New OleDbCommand("SELECT intCandidateAnswerChoiceSysID, intCandidateQuestionSysID FROM tblCandidateQuesHasAnswers WHERE tblCandidateQuesHasAnswers.intCandidateQuestionSysID = " & CInt(strcqid) & "AND" & tblCandidateQuesHasAnswers.intCandidateQuestionSysID = " & CInt(strcqcollect)", OleDbConnection1)

The dataset that contains this table, tblCandidateQuesHasAnswers is dsAnswerChoices which has been included with the form.  

I'm also receiving a related error indicating that the tblCandidateQuesHasAnswers is not declared.

Any assistance that you can offer to resolve this would be greatly appreciated.

Thanks!

Barbara
barbmickAsked:
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SanclerCommented:
There's something very odd about the line you quote.

First, I think the quotes are in the wrong places.  I think the quote after AND needs to go and so does the one after CInt(strcqcollect).

Once you have corrected that, all references to tblCandidateQuesHasAnswers will be within the quotes.  That means that they will be instructions to the parser, referring to a table in the database not in your app's dataset, so the particular error you are reporting will not happen on this line.

The other thing I find odd - although I don't think it is anything to do with the problem you're reporting - is that you are testing the same field - intCandidateQuestionSysID - against two values from two different sources - strcqid and strcqcollect.  There is no "rule" against doing that, but my approach would be first to test whether those values were the same.  If they're not, the test at the database end will return nothing, so why bother to make it?  And if they are the same, why bother to test both of them?

Roger
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