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Easy Example to make DataGridView using c#

Posted on 2006-11-09
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Hi,

I am using C# and making Windows Application in .Net 2005

I want to fetch few records from different table and show it in the GridView

Can anyone give me short and easy example or Code which I can use it.


Thanks,
Dinesh
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Question by:dinesh_bali
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so3 earned 1000 total points
ID: 17918357
Bellow is an example on how to fetch some records from a database access and show in datagridview.
Here is the database link http://www.getquotes-it.com/Articles/DataGridViewDB.zip,  download it and put in directory where is the executable file(In BIN\DEBUG)

Here is a tutorial on how to use datagridview.
http://www.getquotes-it.com/Articles/DataGridView-Tutorial-CSharp.htm



using System;
using System.Collections.Generic;
using System.ComponentModel;
using System.Data;
using System.Drawing;
using System.Windows.Forms;
using System.Data.OleDb;

#endregion

namespace DataGridView_Sample
{
    partial class Form1 : Form
    {
        OleDbConnection dbConn = null;
        OleDbDataAdapter dbDA = null;
        DataSet ds1 = new DataSet();

        public Form1()
        {
            InitializeComponent();
        }
        ~Form1()
        {
            if (dbConn.State != ConnectionState.Closed)
            {
                dbConn.Close();
            }
        }

        protected virtual OleDbCommand getSelectCMD()
        {
            OleDbCommand dbCommand = new OleDbCommand();
            dbCommand.Connection = dbConn;
            dbCommand.CommandText = "SELECT PersonID, PTitle, PName FROM People";
            return dbCommand;
        }

        private void Form1_Load(object sender, EventArgs e)
        {
            string strConn = "Provider=Microsoft.Jet.OLEDB.4.0;Data Source=DataGridViewDB.mdb";

            try
            {
                dbConn = new OleDbConnection(strConn);
                dbConn.Open();
            }
            catch (Exception ex)
            {
                MessageBox.Show(ex.Message);
                return;
            }

            try
            {

                dbDA = new OleDbDataAdapter(getSelectCMD());
                dbDA.Fill(ds1, "results");
            }
            catch (Exception ex)
            {
                MessageBox.Show(ex.Message);
                return;
            }
            this.dataGridView1.DataSource = ds1;
            this.dataGridView1.DataMember = "results";
            this.dataGridView1.Columns[0].Visible = false;
        }
    }
}
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