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str_replace not accepting a number of times parameter

Posted on 2006-11-09
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Last Modified: 2008-03-17
I thought you could limit the number of times str_replace replaces your search string

str_replace("A", "", "ABCDEFGABCDEFG")

gives me

BCDEFBCDEF

I only want the first instance to be replaced

str_replace("A", "", "ABCDEFGABCDEFG", 1)
BCDEFABCDEF
This is giving me the error:
Wrong parameter count for str_replace()

I am not sure which version of php I am using.
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Question by:jackjohnson44
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11 Comments
 
LVL 16

Expert Comment

by:HackneyCab
ID: 17910956
No, but you can set a limit if you use preg_replace() instead.

preg_replace('A', '', 'ABCDEFGABCDEFG', 1);
0
 

Author Comment

by:jackjohnson44
ID: 17910960
will it matter if I am using weird characters?
< > : ; .
0
 
LVL 16

Expert Comment

by:HackneyCab
ID: 17911182
That's a very non-specific question.

Yes, regular expressions are very sensitive to the pattern you supply.

If you only want to extract the stuff before and after a string, then perhaps you're better off using functions like strpos() and substr() to extract before and after the string that you are trying to banish.

If you're more specific, that will help to form a solution.
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LVL 48

Expert Comment

by:hernst42
ID: 17912724
the preg_preplace is not correct. There are the delimiters missing Try

$search = "A";
preg_replace('/'.preg_quote($search, '/') . '/', '', $text, 1);

This will work independend of the character you want to replace
0
 
LVL 16

Expert Comment

by:HackneyCab
ID: 17914039
You're right, I always forget the pattern delimiters the first time I write a preg_replace statement. Your statement is a much more useful one.
0
 

Author Comment

by:jackjohnson44
ID: 17914410
Thanks, will that work for the search string and the replace string?
0
 
LVL 48

Expert Comment

by:hernst42
ID: 17914521
Yup will work for both, as long aus you don't have \ in your replacement string
0
 

Author Comment

by:jackjohnson44
ID: 17914541
What if I do?

I can't guarantee that, it is from a form.

Is there a way to treat search and replace as literals and only replace the first instance?
0
 
LVL 48

Expert Comment

by:hernst42
ID: 17914725
then use

preg_replace('/'.preg_quote($search, '/') . '/', str_replace("\\", "\\\\", $replacement), $text, 1);
0
 

Author Comment

by:jackjohnson44
ID: 17935018
thanks for your help, but I probably should have been more specific.
Here are my delimiters that will be in search and replace.

one is a colon and one a semi colon surrounded with <  > 
<:>  
<;>
0
 
LVL 48

Accepted Solution

by:
hernst42 earned 2000 total points
ID: 17936765
Is the following not working?

$search = '<:>';
$replacement = '<;>';
$text = preg_replace('/'.preg_quote($search, '/') . '/', str_replace("\\", "\\\\", $replacement), $text, 1);
0

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