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how do i create an array of objects by a function return?

Posted on 2006-11-10
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Last Modified: 2010-04-16
here goes experts:

i have a class lets call it myClass.

i want to create an array of myClass objects by a function return like this:

 myClass[]  l_oClass = myFunction();

myFunction looks like this:
 public myClass[] myFunction()
{
    myClass[] l_oClassArray = new myClass[10];

   // alternate code here

    return l_oClassArray;
}

where it says //alternate code here
i have tried to say
  l_oClassArray.Initialize();

or alternatively:
 for( int i=0; i++; i<10)
{ l_oClassArray[i] = new myClass(); }

neither of which stopped me from seeing "object not set to a reference" error when i tried to use the objects

any suggestions?
i have also tried passing the myClass array by ref into the function and then I get the same "not a reference" error when it comes back  even though its been initialized and used inside myFunction before control is returned.

-thanks
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Question by:richardsimnett
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3 Comments
 
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Accepted Solution

by:
ozymandias earned 500 total points
ID: 17916939
for( int i=0; i++; i<10)
{ l_oClassArray[i] = new myClass(); }


the above should work (except that you have a couple of the arguments the wrong way round)

for( int i=0; i<10; i++){
    l_oClassArray[i] = new myClass();
}

0
 

Author Comment

by:richardsimnett
ID: 17917078
>except that you have a couple of the arguments the wrong way round
its always fun without intellisense ;)

ok. so what you are saying is basically that what i am doing should work and that if i am seeing an error it must be generated elsewhere in the code.  (obviously there is alot more going on with my classes than what i posted)

let me wait and see if I get anymore interesting responses before awarding you the points.

thanks alot
0
 

Author Comment

by:richardsimnett
ID: 17917307
werd.
you get the points.

it was right all along.  there was a problem with the X|\/|L parsing that was populating the class.

i didnt believe it was right until you agreed, so your help was instrumental.
0

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