then the expected number of As in the 20th position would be a binomial distributuon with mean 0.79*100 and standard deviation sqrt(100*0.79*(1-0.79))
Title | # Comments | Views | Activity |
---|---|---|---|
Perecntage | 4 | 51 | |
Relative Frequency Assessment | 2 | 27 | |
Probability Distribution | 5 | 35 | |
Error in calculation | 2 | 49 |
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