Harry_Kewell
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Win32 API - Get filename in OpenFile dialog
In Win32 API, I get the path and filename the user select by sending the message
CDM_GETFILEPATH:
SendMessage(hListbox, CDM_GETFILEPATH, iSize, (LPARAM) szFileName)
in which hListBox is the HANDLE of listbox in OpenFile dialog.
I have not been successful yet. Pls help me. Thks so much and Grade A for the solution.
CDM_GETFILEPATH:
SendMessage(hListbox, CDM_GETFILEPATH, iSize, (LPARAM) szFileName)
in which hListBox is the HANDLE of listbox in OpenFile dialog.
I have not been successful yet. Pls help me. Thks so much and Grade A for the solution.
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