Solved

How to input a value for an integer variable

Posted on 2006-11-12
7
174 Views
Last Modified: 2010-03-31
Hi,
I want to have the user input length and width so that my program calculates area and perimeter of a rectangle. How do I write the input statements? Here is my code:

class Rectangle {
private int length;
private int width;

public Rectangle(int l, int w) {
length = l;
width = w;
}

public int calculateArea() {
return length * width;
}

public int calculatePerimeter() {
return (2 * length + 2 * width);
}

public static void main(String args[]) {
    int l,w,area,perimeter;
    System.out.println("Input length:");
    l = input.nextInt(); //????
    System.out.println("Input width:");
    w = input.nextInt();//????
    Rectangle rect = new Rectangle(l,w);
    area = rect.calculateArea();
    perimeter = rect.calculatePerimeter();
    System.out.println("The area of the rectangle is: ");
 
System.out.println(area);
System.out.println("The perimeter of the rectangle is: ");
System.out.println(perimeter);

}
}

Thank you.

0
Comment
Question by:aej1973
  • 3
  • 3
7 Comments
 
LVL 13

Expert Comment

by:kawas
ID: 17927365

quoting: http://javaalmanac.com/egs/java.io/ReadFromStdIn.html

e34. Reading Text from Standard Input

    try {
        BufferedReader in = new BufferedReader(new InputStreamReader(System.in));
        String str = "";
        while (str != null) {
            System.out.print("> prompt ");
            str = in.readLine();
            process(str);
        }
    } catch (IOException e) {
    }
0
 
LVL 13

Expert Comment

by:kawas
ID: 17927372
the method process(str) would be the place that you would do something like:

try {
len = Integer.parseInt(str) ;
} catch (Exception e) {
// bad input
}
0
 

Author Comment

by:aej1973
ID: 17927425
Do I have to include or import any files to use the above code?
0
How to run any project with ease

Manage projects of all sizes how you want. Great for personal to-do lists, project milestones, team priorities and launch plans.
- Combine task lists, docs, spreadsheets, and chat in one
- View and edit from mobile/offline
- Cut down on emails

 
LVL 13

Expert Comment

by:kawas
ID: 17927430
java.io.BufferedReader
java.io.InputStreamReader
0
 

Author Comment

by:aej1973
ID: 17927449
This is my code. Where am I going wrong?

import java.io.BufferedReader;
import java.io.InputStreamReader;

class Rectangle {
private int length;
private int width;
public Rectangle(int l, int w) {
length = l;
width = w;
}
public int calculateArea() {
return length * width;
}
public int calculatePerimeter() {
return (2 * length + 2 * width);
}
public static void main(String args[]) {
    int l,w,area,perimeter;
    System.out.println("Input length:");
    try {
        BufferedReader in = new BufferedReader(new InputStreamReader(System.in));
        String str = "";
        while (str != null) {
            System.out.print("> prompt ");
            str = in.readLine();
            process(str);
        }
    } catch (IOException e) {
    }

    System.out.println("Input width:");
    Rectangle rect = new Rectangle(l,w);
        area = rect.calculateArea();
        perimeter = rect.calculatePerimeter();
        System.out.println("The area of the rectangle is: ");
       
System.out.println(area);
System.out.println("The perimeter of the rectangle is: ");
System.out.println(perimeter);

}
}

0
 
LVL 13

Accepted Solution

by:
marchent earned 75 total points
ID: 17928243
import java.io.BufferedReader;
import java.io.InputStreamReader;
import java.io.IOException;

class Rectangle {
private int length;
private int width;
public Rectangle(int l, int w) {
length = l;
width = w;
}
public int calculateArea() {
return length * width;
}
public int calculatePerimeter() {
return (2 * length + 2 * width);
}
public static void main(String args[]) {
    int l,w,area,perimeter;
    try {
        BufferedReader in = new BufferedReader(new InputStreamReader(System.in));
        System.out.print("Input Length : ");
        l = Integer.parseInt(in.readLine());
        System.out.print("Input width : ");
        w = Integer.parseInt(in.readLine());
        Rectangle rect = new Rectangle(l,w);
        area = rect.calculateArea();
        perimeter = rect.calculatePerimeter();
        System.out.println("The area of the Rectangle is : "+area);
        System.out.println("The perimeter of the Rectangle is : "+perimeter);
       
    } catch (Exception e) {
        System.out.println(e);
    }
}
}
0
 

Author Comment

by:aej1973
ID: 17929412
Thank you.
0

Featured Post

Find Ransomware Secrets With All-Source Analysis

Ransomware has become a major concern for organizations; its prevalence has grown due to past successes achieved by threat actors. While each ransomware variant is different, we’ve seen some common tactics and trends used among the authors of the malware.

Join & Write a Comment

After being asked a question last year, I went into one of my moods where I did some research and code just for the fun and learning of it all.  Subsequently, from this journey, I put together this article on "Range Searching Using Visual Basic.NET …
Introduction This article is the second of three articles that explain why and how the Experts Exchange QA Team does test automation for our web site. This article covers the basic installation and configuration of the test automation tools used by…
Viewers learn about the “while” loop and how to utilize it correctly in Java. Additionally, viewers begin exploring how to include conditional statements within a while loop and avoid an endless loop. Define While Loop: Basic Example: Explanatio…
This video teaches viewers about errors in exception handling.

762 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question

Need Help in Real-Time?

Connect with top rated Experts

21 Experts available now in Live!

Get 1:1 Help Now