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Select value in field containing multiple values

Posted on 2006-11-12
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Last Modified: 2012-05-05
I have a table (user) with a field named membergroupids which contains multiple values seperated by a comma.

The field type is varchar and will contain muiltiple member group id numbers.

for instance

Administrators group is 1
registered is 2
site users is 3
private group is 4

the field can contain this data in random entry.
one record could be   3,4
two could be             1,4
thre could be            4,3
4 could be                2,4


I am trying to figure out the sql statement that would select all records in the table that contain a 4 and ordered by userid.

examples I have tried :

SELECT * FROM user WHERE membergroupids IN (4) = 4 order by userid ASC
SELECT * FROM user WHERE membergroupids >= 4 order by userid ASC
SELECT * FROM user WHERE membergroupids IN ('4') = 4 order by userid ASC

Thank you in advance for your quick response.


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Question by:nurv-x
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6 Comments
 
LVL 19

Expert Comment

by:dmitryz6
ID: 17927860
use like

MS Access example

SELECT * FROM user WHERE membergroupids like *4*

sql server example

SELECT * FROM user WHERE membergroupids like %4%
0
 
LVL 19

Expert Comment

by:dmitryz6
ID: 17927864
use like

MS Access example

SELECT * FROM user WHERE membergroupids like *4* order by userid

sql server example

SELECT * FROM user WHERE membergroupids like %4% order by userid
0
 

Author Comment

by:nurv-x
ID: 17927883
That only returned records in the table that only had a 4 and nothing else in the field.

I should also mention this is php code for connection with a MySQL database.
0
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Accepted Solution

by:
dmitryz6 earned 500 total points
ID: 17927895
SELECT * FROM user WHERE membergroupids like '%4%' order by userid
0
 

Author Comment

by:nurv-x
ID: 17927903
Thank you for your expert help! I was missing the ' ' around the percents!
0
 
LVL 19

Expert Comment

by:dmitryz6
ID: 17927914
You welcome and good luck with your project
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