Solved

Getting a list of Nodes by tag name, starting at a particular Node in the tree...

Posted on 2006-11-14
7
275 Views
Last Modified: 2008-02-01
I'm new to XML. I want to get a list of Nodes by tag name, but starting at some node/depth in the tree - not starting at the top level.

For example, if I have the following simple XML file:

<?xml version="1.0" encoding="ISO-8859-1"?>
<store>
     <item iName="widget1">
          <title> Widget One </title>
          <baseprice> 35.00 </baseprice>
          <repeat> x1 </repeat>
          <repeat> x2 </repeat>
          <repeat> x3 </repeat>
          <more> etc </more>
     </item>

     <item iName="widget2">
          <title> Widget Two </title>
          <baseprice> 1500.00 </baseprice>
          <repeat> y1 </repeat>
          <repeat> y2 </repeat>
          <repeat> y3 </repeat>
          <more> data </more>
     </item>

     <item iName="widget3">
          <title> Widget Three </title>
          <baseprice> 300.00 </baseprice>
     </item>
</store>

and some javascript:

var widget2 = xmlDoc.getElementsByTagName("item")[1];

Can I do something like widget2.getElementsByTagName("repeat") in order to get a list of all the repeat tags within the widget2 tag? In the docs, I don't see any "getElementsByTagName" or similar function in the Node class. Does it only exist at the top level? How do I get a list of tags starting at a particular Node in the tree?
0
Comment
Question by:Melvinivitch
  • 3
  • 2
  • 2
7 Comments
 
LVL 15

Expert Comment

by:ozymandias
ID: 17937175
xmlDoc.SelectNodes("store/item[@iName = 'widget2']/repeat");

This will return an XmlNodeList with all of the repeat nodes under the item with the iName of widget2.
0
 
LVL 60

Expert Comment

by:Geert Bormans
ID: 17937238
Hi Melvinivitch,

Here is what you could do

First you can use SelectNodes to address the node you want to select with XPath
That is a lot more straightforward then using getElementsByTagName.
If you are sure you only want one node instead of a nodelist,
you can use selectSingleNode

You can learn about XPath here
http://www.w3schools.com/xpath/default.asp

var itemNode=oXML.selectNodes("/store/item[@iName = 'widget2']/repeat");

After that you can loop over the nodes like this

                         for (j=0; j<itemNode.length; j++)
                              {
                                  test = test + (itemNode[j].nodeName);
                                  test = test + ("=");
                                  test = test + (itemNode.childNodes[0].nodeValue);
                                  test = test + ("<br />");
                              }          

In this example I write the repeat values in a test string, of course you can use them in your response
The result will be like this
        repeat = y1
        repeat = y2
        repeat = y3            

Cheers!

Geert
0
 

Author Comment

by:Melvinivitch
ID: 17937371
Thanks...

When I use that code: var itemNode=oXML.selectNodes("/store/item[@iName = 'widget2']/repeat");
where oXML is my toplevel xmlDoc object,
and then do: itemNode.childNodes[0].nodeName;
IE gives me this message: "childNodes.0 is null or not an object" ...

Thanks again...
0
MIM Survival Guide for Service Desk Managers

Major incidents can send mastered service desk processes into disorder. Systems and tools produce the data needed to resolve these incidents, but your challenge is getting that information to the right people fast. Check out the Survival Guide and begin bringing order to chaos.

 
LVL 15

Expert Comment

by:ozymandias
ID: 17937514
I am guessing that this :

 test = test + (itemNode.childNodes[0].nodeValue);

should be :

 test = test + (itemNode.childNodes[j].nodeValue);
0
 
LVL 60

Accepted Solution

by:
Geert Bormans earned 325 total points
ID: 17937538
no,
should be test = test + (itemNode[j].childNodes[0].nodeValue);

itemNode[j] is the jth <repeat> element (the jth element in your nodelist)

remeber from one of your previous questions:
childNodes[0].nodeValue is there to get at the text value

you are right, there was a bug in my code, but at a different locaton than you thought

To allign with your question
var itemNode=oXML.selectNodes("/store/item[@iName = 'widget2']/repeat");
should be
var itemNode=xmlDoc.selectNodes("/store/item[@iName = 'widget2']/repeat");

cheers

Geert


0
 

Author Comment

by:Melvinivitch
ID: 17940441
Thanks again.
0
 
LVL 60

Expert Comment

by:Geert Bormans
ID: 17940532
welcome
0

Featured Post

Webinar: Aligning, Automating, Winning

Join Dan Russo, Senior Manager of Operations Intelligence, for an in-depth discussion on how Dealertrack, leading provider of integrated digital solutions for the automotive industry, transformed their DevOps processes to increase collaboration and move with greater velocity.

Question has a verified solution.

If you are experiencing a similar issue, please ask a related question

The Problem How to write an Xquery that works like a SQL outer join, providing placeholders for absent data on the outer side?  I give a bit more background at the end. The situation expressed as relational data Let’s work through this.  I’ve …
Browsing the questions asked to the Experts of this forum, you will be amazed to see how many times people are headaching about monster regular expressions (regex) to select that specific part of some HTML or XML file they want to extract. The examp…
In a recent question (https://www.experts-exchange.com/questions/29004105/Run-AutoHotkey-script-directly-from-Notepad.html) here at Experts Exchange, a member asked how to run an AutoHotkey script (.AHK) directly from Notepad++ (aka NPP). This video…
How to Install VMware Tools in Red Hat Enterprise Linux 6.4 (RHEL 6.4) Step-by-Step Tutorial

679 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question