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select * from vToneAudiogramCurve<br />
where Side in ( select Site &nbsp;from vToneAudiogramCurve group by Side having count(*) = 2 )
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select * from vToneAudiogramCurve
where Side in ( select Site  from vToneAudiogramCurve group by Side having count(*) = 2 )

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you need to specify all the columns except those used for the aggregate functions, for eg, if you have columns Col1, col2 ...Coln <br />
then <br />
<br />
SELECT Col1,Col2<br />
FROM urTable <br />
GROUP BY Col1,Col2 <br />
Having Count(*) &gt;1
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you need to specify all the columns except those used for the aggregate functions, for eg, if you have columns Col1, col2 ...Coln
then

SELECT Col1,Col2
FROM urTable
GROUP BY Col1,Col2
Having Count(*) >1

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<div class="content wysiwyg-content">
Hi, I have written the SQL:<br />
<br />
select * from vToneAudiogramCurve<br />
group by Side having count(*) = 2<br />
<br />
Then I get the error:<br />
Column 'vToneAudiogramCurve.Clien<wbr />t_ID' is invalid in the select list because it is not contained in either an aggregate function or the GROUP BY clause.<br />
<br />
The reason I wan to groop it, and use the having count(') = 2 is that I only want to see results that is in 2 times. How can I get this to work ?
</div>
</div>


Hi, I have written the SQL:

select * from vToneAudiogramCurve
group by Side having count(*) = 2

Then I get the error:
Column 'vToneAudiogramCurve.Client_ID' is invalid in the select list because it is not contained in either an aggregate function or the GROUP BY clause.

The reason I wan to groop it, and use the having count(') = 2 is that I only want to see results that is in 2 times. How can I get this to work ?

Group By, Aggrigate function ?

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