need to set policy on account so it does not lock out........

Ok im hoping someone can help with this one,
We currently are running a 2003 ad, with several sites managed by local it staff.
our default domain controller policy locks out user accounts after 3 invalid passwords to meet SOX requirements.
I current issue is that some of our sites have alot of usere that use the same account, to logon and do generic tasks. The account is locked down to be verry restricted on what the user can do.
But because so many people are using the one account, issues such as some one fat fingering the password or having the caps lock on causes the account to lock out after 3 invalid attempts thus locking out any one who uses the account.
I need a way set no lockout on this one account, but i dont see any options to do this in AD. Is there a way or is there some 3rd party software that would alow me to make this change so the user ID does not lock EVER?
Thanks
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prelude812Asked:
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Netman66Connect With a Mentor Commented:
The only way to do this without 3rd party applications (which I don't know of any off the top) is to put that user account in it's own domain.  By default, the Domain is a Security Boundary - which reinforces Jay's statement that you can only have one Account Policy in the domain that cannot be blocked or overridden.

Contrary to what others on this site have determined, it's not possible.  Placing policies on OUs only affects LOCAL logons to the workstation - NOT domain logons.

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sscuserCommented:
Probably the best solution is to create a seperate OU for those users, create a GP object that does not have lockouts, and apply it to that OU...

So, have the setting undefined on your default policy...create two OU's, one for normal users and one for the non-lockout users, and define the lockout within the OU specific GP's...or just remove the lockout policy altogether.
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Jay_Jay70Commented:
You can have only one password polic per domain. No work arounds (unless you go third party app) but as far as AD is concerned its one and thats it
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Netman66Commented:
I think the answer was provided.
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