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Convert.ToDateTime (string) ---- Easy

Posted on 2006-11-15
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Last Modified: 2012-05-05
Im still pretty new to C#.   How do I get this to work?

I have a string in this format...

"11/8/2006 5:02:2006 PM"

and need to convert this string to a date/time format.


I tried this...

MyClass.MyClassProperty = Convert.ToDateTime("11/8/2006 5:02:2006 PM",DateTimeFormatInfo.CurrentInfo);

But its not working...

I just need to convert it from a string to date/time.

thx!!!!
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Question by:JohnnyKnoxville
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Expert Comment

by:ozymandias
ID: 17949680
string s = "11/8/2006 5:02:2006 PM";
DateTime d = DateTime.ParseExact(s,"dd/M/yyyy h:mm:ss tt", null);
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Expert Comment

by:ozymandias
ID: 17949698
It's a bit hard to tell from your example but the format I have provided is as follows :

dd/M/yyyy h:mm:ss tt

dd = two digit day with leading zero
M = single or double digit month with no leading zero
yyyy = four digit year

h = single digit hour in 12-hour clock format with no leading zero
mm = double digit minute with leading zero
ss : double digit seconds with leading zero !!! NB : you see to have 2006 here, is that a typo !!!!

tt = AP or PM.
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Author Comment

by:JohnnyKnoxville
ID: 17950518
Sorry...my format is mm/dd/yyyy hh:mm:ss tt


Im confused....why would you think that is a typo?  

the year is in a 4 digit format (2006).

When I use this line of code...

MyClass.MyClassProperty = Convert.ToDateTime("11/8/2006 5:02:2006 PM",DateTimeFormatInfo.CurrentInfo);

MyClassProperty is equal to 11/8/2006.....but the time is not included.  I'll try the ParseExact but my mm/dd are inverted so I doubt it'll work for me.
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LVL 15

Expert Comment

by:ozymandias
ID: 17950613
>> Im confused....why would you think that is a typo?  
You have 2006 for the seconds : 5:02:2006.
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Expert Comment

by:ozymandias
ID: 17950633
>>Sorry...my format is mm/dd/yyyy hh:mm:ss tt

No it isn't : you have a single digit day : 8...it should be 11/08/2006
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Author Comment

by:JohnnyKnoxville
ID: 18132574
sorry for the delay with this.  Ive been sidetracked with a bazillion other things.

Ok....my format is ...

mm/D/yyyy hh:mm:ss:tt

11/8/2006 5:02:2006 PM

but it could also be...

11/18/2006 5:02:2006 PM

How do I accommodate a single digit day and two digit day format???
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Accepted Solution

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ozymandias earned 50 total points
ID: 18133124
try both.

Use ParseExact with the double digit day inside a try/catch block.
It if fails catch the error and try with the single digit day.
If that fails throw the error.
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Author Comment

by:JohnnyKnoxville
ID: 18133684
Im brand new to c#.  Can you show me how?

thx
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Expert Comment

by:ozymandias
ID: 18134672
string format1 = "mm/D/yyyy hh:mm:ss tt"; // single digit month
string format2 = "mm/D/yyyy hh:mm:ss tt"; // double digit month
string s = "your date string in either format";

DateTime dt;

try{
    td = DateTime.ParseExact(s, fomat1, null); // try to parse single digit month
}catch{
    // oh no...looks like that didn't work so lets try again
    td = DateTime.ParseExact(s, format2, null); // try to parse double digit month
    // if this fails (i.e. if s does not match either string an error will be thrown here
    // we could enclose the second attempt in another try/catch block if we want
}

// if we make it to here dt will now hold a sucessfully parsed DateTime value.
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Expert Comment

by:ozymandias
ID: 18134685
sorry, error above.

The first two lines should be :

string format1 = "MM/d/yyyy hh:mm:ss tt"; // single digit day
string format2 = "MM/dd/yyyy hh:mm:ss tt"; // double digit day
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