dion_p1
asked on
Restict Random to 6 Characters
Im tryig to randomly generate password 6 Charachters...
Please help its giving me all sorts of size strings
For each strData In strInputData
Dim intPassword
Randomize
intPassword = Int(1234567 * Rnd() + 1)
Set file = objFileSys.CreateTextFile(
file.writeline(strData & "," & intPassword)
Next
file.close
Please help its giving me all sorts of size strings
For each strData In strInputData
Dim intPassword
Randomize
intPassword = Int(1234567 * Rnd() + 1)
Set file = objFileSys.CreateTextFile(
file.writeline(strData & "," & intPassword)
Next
file.close
ASKER
this is vbs
ASKER
I get these results
91666
13173
9935
36523
75810
66838
11205
47953
56761
98588
12475
18743
266
52253
76300
92728
21855
43363
77570
4158
2806
They all Need to be Six Charachters Long
91666
13173
9935
36523
75810
66838
11205
47953
56761
98588
12475
18743
266
52253
76300
92728
21855
43363
77570
4158
2806
They all Need to be Six Charachters Long
Right...the Format function is not available in VBScript...sorrry about that.
Use this line:
file.writeline(strData & "," & Right("00000" & Int(Rnd()*1000000), 6)
You will get numbers like:
001243
198345
000001
Kevin
Use this line:
file.writeline(strData & "," & Right("00000" & Int(Rnd()*1000000), 6)
You will get numbers like:
001243
198345
000001
Kevin
Here is a different way of looking at it...
randomize
msgbox randompass(6)
msgbox randompass(6)
msgbox randompass(6)
private function randomPass(length)
chars = "1234567890" ' <-- this can be changed to include other chars if necessary
for i = 1 to length
randompass = randompass & mid(chars, Int(len(chars) * Rnd + 1), 1)
next
end function
randomize
msgbox randompass(6)
msgbox randompass(6)
msgbox randompass(6)
private function randomPass(length)
chars = "1234567890" ' <-- this can be changed to include other chars if necessary
for i = 1 to length
randompass = randompass & mid(chars, Int(len(chars) * Rnd + 1), 1)
next
end function
ASKER
This is VBScript. I get Syntax Error at Privat Function......
Set oInputFile = objFileSys.OpenTextFile(st
strInputData = Split(oInputFile.ReadAll, vbNewline)
On Error Resume Next
For each strData In strInputData
Set file = objFileSys.CreateTextFile(
file.writeline(strData & "," & randompass(6))
private function randomPass(6)
chars = "1234567890" ' <-- this can be changed to include other chars if necessary
for i = 1 to length
randompass = randompass & mid(chars, Int(len(chars) * Rnd + 1), 1)
next
end function
Next
file.close
Set oInputFile = objFileSys.OpenTextFile(st
strInputData = Split(oInputFile.ReadAll, vbNewline)
On Error Resume Next
For each strData In strInputData
Set file = objFileSys.CreateTextFile(
file.writeline(strData & "," & randompass(6))
private function randomPass(6)
chars = "1234567890" ' <-- this can be changed to include other chars if necessary
for i = 1 to length
randompass = randompass & mid(chars, Int(len(chars) * Rnd + 1), 1)
next
end function
Next
file.close
SOLUTION
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ASKER
Im using your Code Zorvek(Kevin) But still get some funny result...See Below
107375
783995
459640
753688
596094
832730
18758
210368
73953
105452
331694
128249
241
536794
All Random Numbers Must be 6 Charcters Long and No Shorter or Longer.
I also tried Idle Minds Solution and i Get an Error at Function Still.
Thanks In Advanced for you Help.
107375
783995
459640
753688
596094
832730
18758
210368
73953
105452
331694
128249
241
536794
All Random Numbers Must be 6 Charcters Long and No Shorter or Longer.
I also tried Idle Minds Solution and i Get an Error at Function Still.
Thanks In Advanced for you Help.
ASKER CERTIFIED SOLUTION
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This solution is only available to members.
To access this solution, you must be a member of Experts Exchange.
1. Only Randomize once.
2. Be aware of limitations of the VB PRNG:
http://www.15seconds.com/issue/051110.htm
3. Try to avoid or optimize concatenation functions:
Example:
private Function randomPass(parmLen As Long) As String
Dim chars As String
Dim OutBuffer As String
Dim i as Long
Dim charLen as Long
chars = "0123456789ABCDEF" ' <-- these are Hex digits
OutBuffer = Space(parmLen)
charLen = Len(chars)
For i = 1 to parmLen
Mid$(OutBuffer, i, 1) = Mid$(chars, Int(charLen * Rnd + 1), 1)
next
randomPass = OutBuffer
end function
Note: You can also use a byte array quite efficiently and get better performance than this string buffer example.
2. Be aware of limitations of the VB PRNG:
http://www.15seconds.com/issue/051110.htm
3. Try to avoid or optimize concatenation functions:
Example:
private Function randomPass(parmLen As Long) As String
Dim chars As String
Dim OutBuffer As String
Dim i as Long
Dim charLen as Long
chars = "0123456789ABCDEF" ' <-- these are Hex digits
OutBuffer = Space(parmLen)
charLen = Len(chars)
For i = 1 to parmLen
Mid$(OutBuffer, i, 1) = Mid$(chars, Int(charLen * Rnd + 1), 1)
next
randomPass = OutBuffer
end function
Note: You can also use a byte array quite efficiently and get better performance than this string buffer example.
Not sure why your leading zeroes are lost. When I run this script in Explorer all the passwords have six digits:
<html>
<head>
</head>
<body><script type="text/vbscript">
Randomize
For Index = 1 to 100
document.write(Right("0000
Next
</script></body>
</html>
Kevin
<html>
<head>
</head>
<body><script type="text/vbscript">
Randomize
For Index = 1 to 100
document.write(Right("0000
Next
</script></body>
</html>
Kevin
I've republished the VB PRNG article on EE:
http:A_11114.html
http:A_11114.html
file.writeline(strData & "," & Format(Int(Rnd()*1000000),
Kevin