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TreeView Node Tag

Posted on 2006-11-16
3
317 Views
Last Modified: 2011-09-20
Hi Experts,

I have a treeview in my program and wanted to add more details to a node so i created a structure which i than attached to each node.  The problem i am having is that i am not sure how to refer back to the values stored on the tag.  I assumed it would just be something like: node.tag.name but this does not work.

Here is my code:

    Private Structure ProductStruc
        Friend Name As String
        Friend Type As String
        Friend Details As String
        Friend Notes As String
        Friend Qty As Integer
        Friend IsAddition As Boolean
    End Structure

            Dim NodeInfo As ProductStruc
            NodeInfo.Details = Trim(DetailsTXT.Text)
            NodeInfo.IsAddition = IsAddition
            NodeInfo.Name = Trim(ProductCMB.Text)
            NodeInfo.Notes = Trim(ProdNotesTXT.Text)
            NodeInfo.Qty = QuantityNUM.Value
            NodeInfo.Type = Trim(ProdTypeCMB.Text)

            CurComputerNode = ProdView.Nodes.Add(Trim(DetailsTXT.Text))
            CurComputerNode.Tag = NodeInfo

Cheers for any help!
0
Comment
Question by:SteSi
  • 2
3 Comments
 
LVL 7

Expert Comment

by:Mohamed Zedan
ID: 17954481
All you have to do to get what you want is ctype(CurComputerNode.Tag ,NodeInfo).Name
or

dim ni as NodeInfo = ProdView.SelectedNode.tag
'Then use ni as you like .... it is all a matter of casting tag to the right type :)


hope this helps :)
0
 
LVL 5

Expert Comment

by:Venkateswarlu Kaipu
ID: 17954768
dim NodeDetails

NodeDetails = ProdView.SelectedItem.tag

Msgbox NodeDetails
0
 
LVL 7

Accepted Solution

by:
Mohamed Zedan earned 250 total points
ID: 17954783
Sorry I typed nodeinfo instead of ProductStruc thought it was the structure name :)


All you have to do to get what you want is ctype(CurComputerNode.Tag ,ProductStruc).Name
or

dim ni as ProductStruc = ProdView.SelectedNode.tag
'Then use ni as you like .... it is all a matter of casting tag to the right type :)


hope this helps :)
0

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