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Passing arguments to a script through a pipe

Hi!,
    I want to grep through a file and pass the result of the grep command to a shell script(I use $1, $2, etc to recognize arguments). However, I don't know how to do something like this. I don't want to edit the script itself as I may want to grep through another file.

Thank you!
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astracter
Asked:
astracter
1 Solution
 
ravenplCommented:
You can: grep "pattern" file | xargs ./script.sh
But how will You know how many args the script expects?
Also, xargs may call Your script many time if grep output is too long to fit in one script call (argument list is limited in it's length)
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astracterAuthor Commented:
Thank you!,  Actually it's not just a grep...It's a loooooooooooooooong pipe(a lot of seds), The script only expects 1 argument and grep only returns one line. :)

Thank you!
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