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const keyword in functions

Hi Experts,

when functions are declared with const parameters, I think I read it means it will  not be changed within that function.

functionOne( const string& a);    
functionTwo( const Test& t);
funcionThree(const bool c);

Are these always good idea when I am not going to change that parameter inside the function?

Also, functionOne(const string a)  is it going to be the same as functionOne(const string& a)
Other than that I am passing reference rather than value.

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ambuli
Asked:
ambuli
2 Solutions
 
DrAskeCommented:
>>Are these always good idea when I am not going to change that parameter inside the function?
yes :)

>>Also, functionOne(const string a)  is it going to be the same as functionOne(const string& a)
regarding that *string* a will not change inside the function, *YES* it is.
but the first argument is passed by-value, and the other one is passed by-reference
(using  *&* depends on the size of the arguement)

NOTE!!
Many C++ programmers prefer that
1) Modifiable arguments be passed to functions by using pointers.
2) SMALL NONmodifiable arguments be passed by value.
3) HUGE (big) NONmodifiable arguments be passed by using REFERECES TO CONSTANTS.

regards,Ahmad;
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AlexFMCommented:
functionOne( const string& a);    
functionTwo( const Test& t);

These two functions get reference parameter. const definition ensures that parameters cannot be changed. Using const here is OK.

funcionThree(const bool c);
functionOne(const string a);

In this case using const doesn't make sence. Parameters are passed by value, this means, function operates with copy of these parameters. For caller, it doesn't matter whether such parameter is const or not - caller's parameter is not changed in any case.
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ambuliAuthor Commented:
Thank you.  Now, everything makes more sense :-)
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