Static final HashMap.

Posted on 2006-11-20
Last Modified: 2008-11-26
Hi all,

I want to create a hashmap to use as a lookup table. I want it defined close to the code that uses it. Ideally, I'd like it to look something like:

<what goes here?> lookup = {
 {1, "Message 1"},
 {2, "Message 2"},
 {12, "Message 12"},
String message = lookup.get(messageNumber);
if ( message != null ) ...

Can you fill in the <what goes here?> bit?

It will be a simple table, no more than about 30 entries. It wont be used often so efficiency is not an issue.

Thanks all.


Question by:PaulCaswell
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LVL 16

Author Comment

ID: 17978042
It doesnt actually have to be a HashMap. All I really want is to lookup a number in a sparse table and get a string, or null.

LVL 92

Expert Comment

ID: 17978077
Map<Integer, String> lu = new HashMap<Integer, String>();
lu.put(1, "Message 1");
lu.put(2, "Message 2");
lu.put(12, "Message 12");
LVL 16

Author Comment

ID: 17978334
Thanks objects,

This is easy but the problem is that this requires:

1. A class instance hashmap, to ensure that it is only initialised once.
2. A method to initialise it.
3. An invocation.

And they are all in different places in the code. I want them all together in one place so that when someone comes along wanting to change the code, or repeat the technique they can just copy the code and fill in the new table.

Something like this is what you are suggesting I believe:

class MyClass ...
 HashMap lookup; // The class instance.

 void aMethod () {
   String message = getMessage(id); // The invocation.

 String getMessage ( int id ) { // The lookup method.
  String message = "Not Found";
  if ( lookup == null ) {
    lookup = new HashMap ();
    lookup.put(1, "Message 1");
  String found = (String)lookup.get(id);
  if ( found != null ) message = found;
  return message;

As you can see, this breaks the lookup functionality into three separate places. I would like it all in just one place.

If I was doing this in C++ I would do something like:

struct { int id; char * message } [] table = {
  { 1, "Message 1"},
char * message = "Not Found";
for ( int i = 0; i < lengthof(table); i++ ) if ( table[i].id == id ) message = table[i].message;

Do you see what I mean by keeping all the code together?

LVL 92

Accepted Solution

objects earned 250 total points
ID: 17978379
u mean more like:

static final Map<Integer, String> lu = new HashMap<Integer, String>();
   lu.put(1, "Message 1");
   lu.put(2, "Message 2");
   lu.put(12, "Message 12");
LVL 16

Author Comment

ID: 17978459
A static initialiser!!! Of course! <Sound of slapped forehead>

Thank you! :-)


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