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Solved
Case when CHARINDEX
Posted on 2006-11-21
Got two emails:
john.smith@yahoo.com
jsmith@yahoo.com
Need to execute the following logic:
upper(substring(HQ_Ops.inf
The problem is when the email address, 'jsmith@yahoo.com', doesn't contain '.' then the statement fails.
In this case I need to bring just the part before "@", in this example JSMITH.
Thus, I need to write CASE WHEN statement that would capture missing '.' and bring back just 'jsmith' otherwise executes the statement above 'JOHN SMITH'
Any help would be welcome!
john.smith@yahoo.com
jsmith@yahoo.com
Need to execute the following logic:
upper(substring(HQ_Ops.inf
The problem is when the email address, 'jsmith@yahoo.com', doesn't contain '.' then the statement fails.
In this case I need to bring just the part before "@", in this example JSMITH.
Thus, I need to write CASE WHEN statement that would capture missing '.' and bring back just 'jsmith' otherwise executes the statement above 'JOHN SMITH'
Any help would be welcome!
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2
5 Comments
Hi InfoTeam,
case
when charindex('.',HQ_Ops.infot
substring(HQ_Ops.infoteam.
else
-- your statement here
end
Cheers,
Hillwaaa
case
when charindex('.',HQ_Ops.infot
substring(HQ_Ops.infoteam.
else
-- your statement here
end
Cheers,
Hillwaaa
The problem with the statement is that "." exists in yahoo.com and that's why it wouldn't equal 0. We should just try the first part jsmith@
Seems like this one works:
CASE WHEN charindex('.', substring(HQ_Ops.infoteam.
HQ_Ops.infoteam.Project_Lo
charindex('@', HQ_Ops.infoteam.Project_Lo
ELSE upper(substring(HQ_Ops.inf
- 1)) + ' ' + upper(substring(HQ_Ops.inf
+ 1, charindex('@', HQ_Ops.infoteam.Project_Lo
END
CASE WHEN charindex('.', substring(HQ_Ops.infoteam.
HQ_Ops.infoteam.Project_Lo
charindex('@', HQ_Ops.infoteam.Project_Lo
ELSE upper(substring(HQ_Ops.inf
- 1)) + ' ' + upper(substring(HQ_Ops.inf
+ 1, charindex('@', HQ_Ops.infoteam.Project_Lo
END
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