Improve company productivity with a Business Account.Sign Up

x
?
Solved

Generating the random numbers using C#

Posted on 2006-11-22
5
Medium Priority
?
197 Views
Last Modified: 2010-05-18
Hi,

Can you please provide me the working code in C# to generate the random numbers for the following requirements:

1) The Random numbers will have only Alphanumeric values (1,2,3,A,B,c...etc).
2) The function should accept the precision. i.e how much will be the length of the random numbers.
3) The function should accept the input for the count. For example if I input 3 with precision 8. The the code should generate three random numbers, each of length 8.
4) The output should be in the format: Number 1: ABCDEFGH, Number 2:ZZZZZZZ and so on

How can I do this?

Thanks for the help.

Run2004
0
Comment
Question by:run2004
  • 2
  • 2
5 Comments
 
LVL 23

Expert Comment

by:adathelad
ID: 17996888
Hi run2004,

This function will return an array of random numbers as you require:
private string[] GenerateRandomNumbers(int Count, int Precision)
        {
            string[] numbers = new String[Count];
            System.Text.StringBuilder numberBuilder = new System.Text.StringBuilder();
            string newNumber;

            for (int loop=0; loop < Count; loop++)
            {
                numberBuilder.Length = 0;
                while (numberBuilder.ToString().Length < Precision)
                {
                    numberBuilder.Append(System.Guid.NewGuid().ToString().Replace("-", ""));
                }

                newNumber = numberBuilder.ToString();
                if (newNumber.Length > Precision)
                {
                    newNumber = newNumber.Substring(0, Precision);
                }

                numbers[loop] = newNumber;
            }

            return numbers;
        }

0
 
LVL 23

Accepted Solution

by:
adathelad earned 1400 total points
ID: 17996929
To get the output in the format "Number 1: .....", you can use this version:
private string GenerateRandomNumbers(int Count, int Precision)
        {
            System.Text.StringBuilder numberBuilder = new System.Text.StringBuilder();
            System.Text.StringBuilder numberString = new System.Text.StringBuilder();
            string newNumber;

            for (int loop=0; loop < Count; loop++)
            {
                numberBuilder.Length = 0;
                while (numberBuilder.ToString().Length < Precision)
                {
                    numberBuilder.Append(System.Guid.NewGuid().ToString().Replace("-", ""));
                }

                newNumber = numberBuilder.ToString();
                if (newNumber.Length > Precision)
                {
                    newNumber = newNumber.Substring(0, Precision);
                }

                numberString.Append("Number ");
                numberString.Append((loop + 1).ToString());
                numberString.Append(": ");
                numberString.Append(newNumber);

                if ((loop+1) < Count) { numberString.Append(", "); }
            }

            return numberString.ToString();
        }
0
 
LVL 1

Author Comment

by:run2004
ID: 17999589
This is a good one, but I just wanted to know how good it is to use the random class to generate the random numbers. There is one more observation, the output doesn't contain upper case letters. Is there a way to have both in one place.

Thanks for the fast response.
0
 
LVL 11

Assisted Solution

by:Expert1701
Expert1701 earned 600 total points
ID: 18001422
Here is a sample of output,

  T9bhygXK
  by1Gl7aW
  bnhMe6iZ

produced by this program:

  static Random random = new Random();

  static void Main()
  {
    foreach (string result in GenerateRandoms(3, 8))
      Console.WriteLine(result);

    Console.ReadLine();
  }

  static string[] GenerateRandoms(int number, int precision)
  {
    string[] list = new string[number];
   
    for (int i = 0; i < number; i++)
      list[i] = GenerateRandom(precision);
   
    return list;
  }

  static string GenerateRandom(int precision)
  {
    char[] list = new char[precision];

    for (int i = 0; i < precision; i++)
    {
      int next = random.Next() % 62;
      if (next < 10)
        list[i] = (char)('0' + next);
      else if (next < 36)
        list[i] = (char)('A' + next - 10);
      else
        list[i] = (char)('a' + next - 36);
    }

    return new string(list);
  }
0
 
LVL 11

Expert Comment

by:Expert1701
ID: 18017562
run2004, did the sample application I posted meet your requirements?
0

Featured Post

Free Tool: IP Lookup

Get more info about an IP address or domain name, such as organization, abuse contacts and geolocation.

One of a set of tools we are providing to everyone as a way of saying thank you for being a part of the community.

Question has a verified solution.

Are you are experiencing a similar issue? Get a personalized answer when you ask a related question.

Have a better answer? Share it in a comment.

Join & Write a Comment

Article by: Najam
Having new technologies does not mean they will completely replace old components.  Recently I had to create WCF that will be called by VB6 component.  Here I will describe what steps one should follow while doing so, please feel free to post any qu…
This article is for Object-Oriented Programming (OOP) beginners. An Interface contains declarations of events, indexers, methods and/or properties. Any class which implements the Interface should provide the concrete implementation for each Inter…
In the video, one can understand the process of resizing images in single or bulk. Kernel Bulk Image Resizer is an easy to use tool for resizing large number of images. One can add and resize multiple images with this tool in single go. The video sh…
Watch the video to know the process of migration of Exchange or Office 365 mailboxes in absence of MS Outlook. It is an eminent tool which can easily migrate Public, Archive user mailboxes from one another Exchange server and Office 365. Kernel Migr…

585 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question