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regular expression

Posted on 2006-11-23
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Last Modified: 2010-04-16
i need a regular expression which will match sequence with aplhanumeric characters and containig chracters : , and ., if the sequence contain anything other than these chracters it will discard it
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Question by:jyotishb
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5 Comments
 
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Expert Comment

by:pepr
ID: 18005103
Try this script to see if it is the answer to your question:

import re

rex = re.compile(r'[^a-zA-Z0-9:.]+')    # It is more efficient to compile the pattern
                                        # if the regular expression is to be used intensively.

s = 'abc 11. 5. 2006  14:35 <?+- ABC _' # the string to be processed
print s
s2 = rex.sub('', s)                     # the unwanted sequences erased
print s2
s3 = rex.sub(' ', s)                    # the unwanted sequences replaced by spaces
print s3
s4 = rex.sub('+++', s)                  # the unwanted sequences replaced by a chosen string
print s4

It will produce the followint output:

abc 11. 5. 2006  14:35 <?+- ABC _
abc11.5.200614:35ABC
abc 11. 5. 2006 14:35 ABC
abc+++11.+++5.+++2006+++14:35+++ABC+++


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Accepted Solution

by:
ramrom earned 500 total points
ID: 18005109
[^a-zA-Z0-9:,.] used with search will return a match object if any character not in a-zA-Z0-9:,. is in the sequence.
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LVL 17

Expert Comment

by:ramrom
ID: 18005114
"if the sequence contain anything other than these chracters it will discard it" discard the offending character or discard the sequence?
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Author Comment

by:jyotishb
ID: 18005391
discard the sequence
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LVL 17

Expert Comment

by:ramrom
ID: 18005593
OK then you want something like:

if re.search("[^a-zA-Z0-9:,.]", sequence): discard sequence

Also, as pepr points out you may compile the pattern first.
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