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using boost thread for a simple code

Posted on 2006-11-23
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863 Views
Last Modified: 2013-12-14
Hi
the code below compiles and runs, but does not do what I want.
how can I get the code below to print out:
"I am child 1sub thread called."

thanks

******************************************************************
#include <boost/thread/thread.hpp>
#include <string>
#include <iostream>
using namespace std;

class Child
{
  string c;
public:
  Child(string x):c(x){ }
  void operator()(){
    cout << c << " sub thread called." << endl;
  }
};

class Parent
{
  string p;
public:
  Parent(string x):p(x){}
  void operator()(){
    cout << p << "thread called." << endl;
    Child c1("I am child 1");
    boost::thread c1t(c1);
  }
};
 
int main(){
  Parent p1("I am parent 1: ");
  boost::thread p1t(p1);
}
 
0
Comment
Question by:samj
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8 Comments
 
LVL 3

Expert Comment

by:Akumas
ID: 18006817
not quite clear...

first , cout is not thread safe, the output result is hard to predict.
second, after you create thread, us thread.join to wait thread finish.

like this:

    Child c1("I am child 1");
    boost::thread c1t(c1);
    c1t.join();//wait thread finish
0
 

Author Comment

by:samj
ID: 18009061
that did not quite fix it. however the fix was to add join() to each of the Parent and Child objects like this

#include <boost/thread/thread.hpp>
#include <string>
#include <iostream>
using namespace std;

class Child
{
  string c;
public:
  Child(string x):c(x){ }
  void operator()(){
    cout << c << " sub thread called." << endl;
  }
};

class Parent
{
  string p;
public:
  Parent(string x):p(x){}
  void operator()(){
    cout << p << "thread called." << endl;
    Child c1("I am child 1");
    boost::thread c1t(c1);
    c1t.join();
  }
};
 
int main(){
  Parent p1("I am parent 1: ");
  boost::thread p1t(p1);
  p1t.join();
}
 
0
 

Author Comment

by:samj
ID: 18009096
I will ask to split the points and award you 75 for your attempt.
0
 
LVL 3

Expert Comment

by:Akumas
ID: 18010277
yes, it's just a example.
anyway, it's a pleasure to help:)
0
 
LVL 1

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