Solved

Im working on a simple array that  takes 3 values then prints the values and sums them ,but I keep getting this int cannot be dereferenced error

Posted on 2006-11-27
9
199 Views
Last Modified: 2010-03-31
/****************************************************************/
//Program:Array.java
//Date:8/06/03
//
//This program demonstrates the use of arrays in storing data.
//The student will enter and process data according to the
//exercises.
/****************************************************************/

import javax.swing.JOptionPane;

public class Array{

      public static void main ( String args[] ){
      
            final int SIZE = 3;                        //The size of our array
            int array1[] = new int[SIZE];      //Array declaration
      
            String tempHolder;                        // temporary holder for String input
            
            //Prompt to enter 'SIZE' number of integers
      for( int i = 0; i < SIZE; i++ )
{
            tempHolder = JOptionPane.showInputDialog("Enter an integer: ");
            array1[i] = Integer.parseInt(tempHolder);
}

String outputString = "";

      for( int i = 0; i < array1[i].length; i++ )
{
            outputString = outputString + "Index " + i;
            outputString += " contains value: " + array1[i] + "\n";
}
JOptionPane.showMessageDialog ( null, outputString);
      

            System.exit(0);
      }
}
0
Comment
Question by:lusius188
9 Comments
 
LVL 23

Expert Comment

by:Ajay-Singh
ID: 18020196
> for( int i = 0; i < array1[i].length; i++ )
should be


for (int i = 0; i < array1.length; i++) {
0
 
LVL 10

Accepted Solution

by:
ADSLMark earned 84 total points
ID: 18020204
The variable array1 is a single dimension array. If you want to get the length of this array you should do:

array1.length

In the for loop you do:

array1[i].length;

which is read as:

array1[i] (=i-th element in array1, which results in an integer (int))
and then you want to access attribuut .length of an integer (which is not possible)

So just remove the [i] and it should be working.
Also it might not be preferable to name your class Array (without putting it into another package) since Array is a default class in the Java package.

Mark
0
 

Assisted Solution

by:ddurmon
ddurmon earned 83 total points
ID: 18025310
ADSLMark is correct. A better coding standard to use is as follows:

int[] array1 = new int[SIZE];

The reason for this is that when reading this code the statement clearly says
An integer array NAMED array1 = a new array of integer size X.

The way you were coding added to your confusion in your last loop because while what you declared is TECHNICALLY correct at the top it reads as if you have a integer named array1 oh and by the way the integer is an array of integers.  It is not WRONG, it is just easier to understand when referencing.  

Take a look at "The Elements of Java Style" book (ISBN 0-521-77768-2) on page 26 example 27.  While not specifically identifying the array question, you will notice that they do as I have recommended.  

ADSLMark is correct in that if you do as he has stated it will fix your "int can not be dereferenced error".

To avoid making similar mistakes in the future I would recommend declarations be in the following format:
<TYPE>  <VARNAME>  [= <INITIALIZATION>]

for example:
int[] array1 = new int[10];
char[] myText = new char[1024];

Hope this helps and your assignment gets an A :)

Dwight
0
6 Surprising Benefits of Threat Intelligence

All sorts of threat intelligence is available on the web. Intelligence you can learn from, and use to anticipate and prepare for future attacks.

 
LVL 6

Expert Comment

by:SamsonChung
ID: 18029171
I would change the name Array to myArray or something else.

I believe Object.Array is defined in Java.
0
 
LVL 23

Expert Comment

by:Ajay-Singh
ID: 18030724
> I believe Object.Array is defined in Java.

Not defined. please please do *not* to post comments if you are not sure.
0
 
LVL 10

Expert Comment

by:ADSLMark
ID: 18030742
0
 
LVL 23

Assisted Solution

by:Ajay-Singh
Ajay-Singh earned 83 total points
ID: 18030816
> How about: java.lang.reflect.Array

Yes. In fact there are be other third party Array classes as well. My point was there is nothing called "Object.Array" in java - there is no field (or static class) named "Array" in java.lang.Object class.
0

Featured Post

Do You Know the 4 Main Threat Actor Types?

Do you know the main threat actor types? Most attackers fall into one of four categories, each with their own favored tactics, techniques, and procedures.

Join & Write a Comment

Suggested Solutions

Title # Comments Views Activity
countHi2 challenge 7 44
Exception after setting jdbc session management 2 38
word0 challenge 4 54
Java JRE greater than 1.6 5 24
For beginner Java programmers or at least those new to the Eclipse IDE, the following tutorial will show some (four) ways in which you can import your Java projects to your Eclipse workbench. Introduction While learning Java can be done with…
Introduction This article is the second of three articles that explain why and how the Experts Exchange QA Team does test automation for our web site. This article covers the basic installation and configuration of the test automation tools used by…
Viewers learn about the third conditional statement “else if” and use it in an example program. Then additional information about conditional statements is provided, covering the topic thoroughly. Viewers learn about the third conditional statement …
This tutorial will introduce the viewer to VisualVM for the Java platform application. This video explains an example program and covers the Overview, Monitor, and Heap Dump tabs.

760 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question

Need Help in Real-Time?

Connect with top rated Experts

22 Experts available now in Live!

Get 1:1 Help Now