Welcome to Experts Exchange

Add your voice to the tech community where 5M+ people, just like you, are talking about what matters.

  • Help others & share knowledge
  • Earn cash & points
  • Learn & ask questions
Solved

java.net.BindException: Cannot assign requested address: Cannot bind

Posted on 2006-11-30
3
9,720 Views
Last Modified: 2012-06-27
Hi,

When I try to connect to a machine (229.2.0.2 on port 9202) I get the java.net.BindException.

When I try connecting to localhost, I do not get the exception.  Also, I do not get an exception when I try connecting to a machine on my local network.

I would like to know why I cannot bind to this address, and I would like to know a workaround or solution.

Thanks!

Output of TestServer:

Host Address=229.2.0.1
Port        =9201
Exception in thread "main" java.net.BindException: Cannot assign requested address: Cannot bind
      at java.net.PlainDatagramSocketImpl.bind0(Native Method)
      at java.net.PlainDatagramSocketImpl.bind(PlainDatagramSocketImpl.java:82)
      at java.net.DatagramSocket.bind(DatagramSocket.java:368)
      at java.net.MulticastSocket.<init>(MulticastSocket.java:147)
      at TestServer.main(TestServer.java:17)
      at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
      at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:39)
      at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:25)
      at java.lang.reflect.Method.invoke(Method.java:585)
      at com.intellij.rt.execution.application.AppMain.main(AppMain.java:90)

TestServer source code:

import java.net.*;

public class TestServer {

 public static void main(String[] args) throws Exception {

   if (args.length != 2) {
     System.out.println("Usage: java TestServer <host_address_ipv6> <port>");
     System.exit(1);
   }

   System.out.println("Host Address="+args[0]);
   System.out.println("Port        ="+args[1]);

   ServerSocket ss = new ServerSocket();
   InetSocketAddress isa = new InetSocketAddress(InetAddress.getByName(args[0]), Integer.parseInt(args[1]));
   new MulticastSocket(isa);

   System.out.println("ServerSocket Bound");

 //  ss.accept();
 }
}
0
Comment
Question by:Gezna
3 Comments
 
LVL 23

Expert Comment

by:Ajay-Singh
ID: 18047358
the host should either be localhost, or any other host address of local computer - should never be remote host address
0
 
LVL 12

Expert Comment

by:enachemc
ID: 18048221
make sure that there is no other process that uses that port.
0
 

Accepted Solution

by:
geoff2k earned 500 total points
ID: 18048679
You can only bind to ip addresses that are bound to an adapter on your local machine.   Under Windows you can use "ipconfig /all" to get a list of all the addresses that are local to you:

c:>ipconfig /all | find "IP Address"
        IP Address. . . . . . . . . . . . : 192.168.47.1
        IP Address. . . . . . . . . . . . : 192.168.159.1
        IP Address. . . . . . . . . . . . : 10.0.0.14
        IP Address. . . . . . . . . . . . : 10.31.0.240

I can successfully bind to any of the above addresses as well as 127.0.0.1 (localhost).  Any other procudes the error you mention.
0

Featured Post

Free Tool: Port Scanner

Check which ports are open to the outside world. Helps make sure that your firewall rules are working as intended.

One of a set of tools we are providing to everyone as a way of saying thank you for being a part of the community.

Question has a verified solution.

If you are experiencing a similar issue, please ask a related question

Suggested Solutions

This was posted to the Netbeans forum a Feb, 2010 and I also sent it to Verisign. Who didn't help much in my struggles to get my application signed. ------------------------- Start The idea here is to target your cell phones with the correct…
Introduction This article is the first of three articles that explain why and how the Experts Exchange QA Team does test automation for our web site. This article explains our test automation goals. Then rationale is given for the tools we use to a…
Viewers will learn about basic arrays, how to declare them, and how to use them. Introduction and definition: Declare an array and cover the syntax of declaring them: Initialize every index in the created array: Example/Features of a basic arr…
This video teaches viewers about errors in exception handling.

808 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question