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error C2110: cannot add two pointers

Posted on 2006-11-30
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Last Modified: 2013-11-20
Hi guys,

Can somebody help me fix this warning please?

error C2110: cannot add two pointers


Here's my code:

      CString msgTmp;
      msgTmp = "From: "+TargetPath;
      msgTmp += "\nTo: "+argv[2];

      AfxMessageBox(msgTmp);



Cheers!
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Question by:Cyber-Drugs
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6 Comments
 
LVL 30

Accepted Solution

by:
Axter earned 2000 total points
ID: 18048060
Try the following:
     msgTmp = CString(_T("From: ")) + TargetPath;
     msgTmp += CString(_T("\nTo: ")) + argv[2];
0
 
LVL 30

Assisted Solution

by:Axter
Axter earned 2000 total points
ID: 18048074
or.....
     msgTmp = "From: ";
     msgTmp += TargetPath;
     msgTmp += "\nTo: ";
     msgTmp += argv[2];
0
 
LVL 4

Author Comment

by:Cyber-Drugs
ID: 18048117
Cheers Axter!
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LVL 4

Expert Comment

by:bdunz19
ID: 18048140
Axter's solution is correct, I just want to add some important info for you to understand why it's not working. Again, give Axter the points.

The CString class has an "operator+" which will allow you to add a char* type, or const char*, ect to the CString. So when you do an operation like:

CString tmp, tmp2;
tmp = tmp2 + "test"; // This will work because it's like saying tmp = the CString (tmp2) addition of the const char* "test"

tmp += "\nTo: "+argv[2]; // This won't work because you're trying to add a const char* plus a char*.

So when you try to add "\nTo: "+argv[2]; argv[2] is most likely in your program defined as a char*. So what you are trying to do is add a const char* with a char* and because const char* is not a class like CString it has no operator+ and doesn't know what you want to do with it. The CString::operator+ method is what allows CStrings to be able to add characters to your variable because it has the built in method to hadle the operation.

Hope that makes more sense to you when dealing with future CString operations.
0
 
LVL 4

Author Comment

by:Cyber-Drugs
ID: 18048202
Thank you very much for that breakdown Brandon, highly appreciate your time for explaining that to me. :)
0
 
LVL 30

Expert Comment

by:Axter
ID: 18048223
FYI:
The same can be said for std::string and std::wstring, and they both have similar work around.
0

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