Automatic date archive

Posted on 2006-12-01
Medium Priority
Last Modified: 2011-10-03
Hi there,

I am building a system that will monitor mortgage policies indefintiely from the date they are added to the system.  I therefore want to be able to see on a monthly, quarterly, yearly and bi-yearly basis how many mortgages were sold and by which advisers within the company.

When the policies are added to the database, they are added with the ( day its added) date along with the month number and year.


policy_added = 20061201
policy_added_mon = 12
policy_added_yr = 2006

Now i know how to manually add a select statement to see all of these policies by looking at thsi older question = http://www.experts-exchange.com/Web/Web_Languages/PHP/Q_21596727.html?query=archive&topics=103&showAll=true

But as the months and years go on i want the archive to build itself. Starting by a page where you select the timeframe you want to see


You then select the year and then the month
year and then quarter 1,2,3 or 4

But as a new month and in turn quarter and years go by i need these to automagically add to the archive links.

Any advice would be greatly appreciated!! Cheers :)
Question by:drews1f
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Accepted Solution

John Kawakami earned 1000 total points
ID: 18058334
This is a pretty general question.

If you have a relatively small number of policies (like a few hundred per year), and not many people view them too often, you can just write up the report queries in SQL, and do the queries dynamically.

First, come up with the report query:

SELECT policy, seller FROM sales GROUP BY seller ORDER BY seller

Then, based on the interval, you add an WHERE clause:

$start = "1/1/2006";
$end = "1/4/2006";
$sql = "SELECT policy, seller FROM sales WHERE saleDate >= $start AND saleDate < $end  GROUP BY seller ORDER BY seller";

The $start and $end should be set based on the type of query:
    function reportQuery( $queryType = 'annual', $year = Null, $month = Null )
        // $year and $month should be the user-selected year and month
        // if they are not set, they default to the current year and month
        // $query type is set to the type of query you want
        if (!isset($queryType))
            $queryType = 'annual';
        if (!isset($year))
            $year = date('Y');
        if (!isset($month))
            $month = date('M');
        switch ($queryType) {
            case 'm':
                   if ($month==12) {
                       $start = "$month/1/$year"; $end = "1/1/".($year+1);
                   } else {
                       $start = "$month/1/$year"; $end = ($month+1)."/1/$year";
            case 'q1':
                   $start = "1/1/$year"; $end = "1/4/$year";
            case 'q2':
                   $start = "1/4/$year"; $end = "1/7/$year";
            case 'q3':
                   $start = "1/7/$year"; $end = "1/10/$year";
            case 'q4':
                   $start = "1/10/$year"; $end = "1/12/$year";
            case 'annual':
                   $start = "1/1/$year"; $end = "1/1/".($year+1);
            case 'biannual':
                   $start = "1/1/$year"; $end = "1/1/".($year+2);
        $sql = "SELECT policy, seller FROM sales WHERE saleDate >= $start AND saleDate < $end  GROUP BY seller ORDER BY seller";
        return $sql;

Author Comment

ID: 18059370
Can i use an 'UNTIL' statement to work backwards how many years there have been? and in turn how many months etc?

Ie if we were in 2008 and the first policies were added on august 2005

the loop will get the current year
then display it (2008)
then unless the current year is '2005' it does '-1 year'
then displays it (2007)
then unless the current year is '2005' it does '-1 year'
then displays it (2006)
then unless the current year is '2005' it does '-1 year'
then displays it (2005)

I can then do the same for months using the year logic :o

Expert Comment

by:John Kawakami
ID: 18092399
I'm not understanding the second question.

If you want to show multiple years, you can just specify a new interval like "5years" and then set up the dates accordingly.

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